Can you define an argument as a reference type?
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Answer / Amrit Kumar Vashistha
In PHP, there is no concept of passing arguments by reference directly. However, you can achieve this using the "&" operator before the function parameter. Here's an example:
```php
function changeValue(&$myVar) {
$myVar = 'new value';
}
$myVar = 'original value';
changeValue($myVar);
echo $myVar; // outputs 'new value'
```
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