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to list a particular line in the file
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Answer / jam
To print a specific line without using a string.
sed -n '1p' <filename>
Where 1 is teh line number
| Is This Answer Correct ? | 5 Yes | 0 No |
Answer / deepak
grep -i " give_the search keyword here" (specify the directory location/file to search)
| Is This Answer Correct ? | 3 Yes | 2 No |
sed -n '1p' <filename>
head -n filename | tail -1
(change n as per your requirements)
| Is This Answer Correct ? | 0 Yes | 0 No |
Answer / ranjitha
using head and tail command we can print the required line
as an output.
| Is This Answer Correct ? | 2 Yes | 7 No |
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When i run a programm of orphan process. Instead of getting child's parent (ppid)=1 ..i get 1400 and it varies as per system. How can i findthe right soluion??? My pgm: #include<stdlib.h> # include <stdio.h> int main() { int pid; pid=fork(); if(pid < 0) {exit(-1);} else if(pid==0) { printf("Child Process is Sleeping ..."); sleep(10); printf("Orphan Child's Parent ID : %u ",getppid()); } else { printf("Parent Process Completed ... %u ",getpid()); exit(0); } return 0; } Output:
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