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How to create the PHP Script to Calculate the Age Using the
Inputs Of our Birth date and the Current date?
- 6 Answers
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Answers were Sorted based on User's Feedback
Answer / sindhu
<?
$year=$_POST['year'];
$mon=$_POST['mon'];
$dt=$_POST['dt'];
if ($_POST['submit']!="")
{
$a=date("d");
echo "this is cu date".$a."<br>";
$b=date("m");
echo "this is cu month".$b."<br>";
$c=date("Y");
echo "this is cu date".$c."<br>";
if ($b < $mon && $a > $dt )
{
$age=$c-$year-1;
$e=12-$mon;
$month=$b+$e;
$f=$a-$dt;
echo "You
are"." ".$age."years"." ".$month."Months"." ".$f."Days"." "."old";
}
if ($b < $mon && $a < $dt )
{
$age=$c-$year-1;
$e=12-$mon-1;
$month=$b+$e;
$f=$dt-$a;
$g=30-$f;
echo
$age."years"." ".$month."Months"." ".$g."Days";
}
if ($b > $mon && $a > $dt)
{
$age=$c-$year;
$month=$b-$mon;
$f=$a-$dt;
echo
$age."years"." ".$month."Months"." ".$f."Days";
}
if ($b > $mon && $a < $dt)
{
$age=$c-$year;
$month=$b-$mon-1;
$f=$dt-$a;
$g=30-$f;
echo
$age."years"." ".$month."Months"." ".$g."Days";
}
if ($b == $mon && $a < $dt )
{
$age=$c-$year-1;
$month=11;
$f=$dt-$a;
$g=30-$f;
echo
$age."years"." ".$month."Months"." ".$g."Days";
}
if ($b == $mon && $a > $dt )
{
$age=$c-$year;
$month=0;
$f=$a-$dt;
echo
$age."years"." ".$month."Months"." ".$f."Days";
}
if ($b < $mon && $a == $dt )
{
$age=$c-$year-1;
$e=$mon-$b;
$month=12-$e;
$f=0;
echo
$age."years"." ".$month."Months"." ".$f."Days";
}
if ($b > $mon && $a == $dt )
{
$age=$c-$year;
$month=$b-$mon;
$f=0;
echo
$age."years"." ".$month."Months"." ".$f."Days";
}
if ($b == $mon && $a == $dt )
{
$age=$c-$year;
$month=0;
$f=0;
echo
$age."years"." ".$month."Months"." ".$f."Days";
}
}
?>
| Is This Answer Correct ? | 6 Yes | 3 No |
Answer / prakash.matte
<?php
$dob = '29-05-1986';
$age = date('Y') - date('Y', strtotime($dob));
if (date('md') < date('md', strtotime($dob))) {
$age--;
}
echo $age;
?>
| Is This Answer Correct ? | 5 Yes | 2 No |
Answer / nirav desai
<?php
$a = date('Y',strtotime('1985-10-15'));
$b = date('Y');
$c = $b-$a;
echo "Current age is:: ".$c." Years .";
?>
| Is This Answer Correct ? | 5 Yes | 3 No |
Answer / king
<?php
//calculate years of age (input string: YYYY-MM-DD)
function birthday ($birthday){
list($year,$month,$day) = explode("-",$birthday);
$year_diff = date("Y") - $year;
$month_diff = date("m") - $month;
$day_diff = date("d") - $day;
if ($day_diff < 0 || $month_diff < 0)
$year_diff--;
return $year_diff;
}
?>
| Is This Answer Correct ? | 6 Yes | 8 No |
Answer / sandhya
<?php
$date1 = time();
$date2 = mktime(0,0,0,02,01,1979);
$ddif = $date1 - $date2;
$age = floor(($ddif/(60*60*24))/365);
echo $age;
?>
| Is This Answer Correct ? | 0 Yes | 6 No |
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