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We have drive feeding an output contactor for a 5000 hp motor @ 5kV application. The motor FLA is 629amps x 1.25% service factor = 786.25 amps The cable that we current have in place between the drive and the output contactor is 350kcmil- MV-105 (parallel cables). Per the NEC table 310.60 (C) (69). This show the cable ampacity is at 615 amps per cable for a rating of 1230 amps. We have derated the cable for the cable tray and the multiple cables application and our calculations show that after the correction factor factor we are at 922amps. 1230 amps x .75% correction factor factor = 922.5 amps. The customer is driving us to then use another safety factor of .25% off of the already derated cable. Can you please provide a longhand calculation for your solution on this application?
Hi, I got error message as "object does not support this property or method: "Test.Actions" when i execute the following line of script on QTP 9.0 Dim qtApp, qtRep Set qtApp = CreateObject("QuickTest.Application") Set qtRep = qtApp.Test.Actions("Action1").ObjectRepositories Can anyone tell me where i am wrong.
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If you are made the compaign leader for a particular political party .How will you use your leader ship skills to motivate your party men to ensure success of the party nominee in the elections? (Focus on the individual motivate and apply leadership style).
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src name sex a,male b,female c,male d,female Required output : male female a,b c,d tried pivot but was not successfull select * from src pivot (max(name) for sex in ('MALE','FEMALE'));