cement and sand required for one block of size 0.23*0.15*0.46
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Answer Posted / Ashish Rastogi
To calculate the quantity of cement and sand required for a concrete block with dimensions 0.23 m * 0.15 m * 0.46 m, we first need to determine the volume of the block. The volume is 0.23 m * 0.15 m * 0.46 m = 0.01893 m³. Assuming a ratio of 1:3 for cement and sand (i.e., 1 part cement to 3 parts sand), the quantity of cement required would be approximately 0.01893 m³ / 0.25 = 0.07572 m³, and the quantity of sand required would be 3 * 0.07572 m³ = 0.22716 m³.
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