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We were required to write a program to check whether the
given number was of the form 3^n. ( i.e. 3 to the power n).
I knew that it can be done by bit manipulation but couldn't
make out the logic.
i want a solution in C/C++ language
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Answer Posted / sreejesh1987
#include<stdio.h>
#include<conio.h>
void main()
{
int count=0,n,d;
clrscr();
printf("\tDigit 3powern\n");
printf("Enter a no:");
scanf("%d",&n);
d=n;
while(d%3==0)
{
d=d/3;
count++;
}
if(d==1)
printf("\nNumber %d is of 3^%d format",n,count);
else
printf("\nNumber %d is not in 3^n format",n);
getch();
}
| Is This Answer Correct ? | 17 Yes | 6 No |
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