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Categories >> Software >> Operating-Systems >> Operating-Systems-General-Concepts
 
 
 
Question 
abcD+abcd+aBCd+aBCD
    then the simplified function is
    ( Capital letters are copliments of corresponding letters
      A=compliment of a)
 
   [a] a   [b] ab  [c] abc  [d] a(bc)* [e] mone
   (bc)*=compliment of bc
 Question Submitted By :: Guest
I also faced this Question!!     Rank Answer Posted By  
 
Answer
 
since capital letters are the complements...
(abcD+abcd)+(aBCd+aBCD)..taking them separately...
solving for the 1st bracket...abc(D+d)=abc{D+d=0}
solving for the 2nd bracket...aBC(d+D)=aBC{D+d=0}
==abc+aBC=a(bc+BC)
         =a*0
         =0
 
0
Ramya
 
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