ans=24
no divisible by 3:
102,105,108,111,114,117,120,123,126,129,132,135,138,141,144,
147,150.
no divisible by 5:
100,105,110,115,120,125,130,135,140,145,150.

now strike out 105 120 135 150,as it is present in 
both.remaining totally 24 nos are present,which cannot be 
evenly divided 3 or 5.(means wen divisible by 3 it is not 
by 5 n vice versa)