ALLInterview.com :: Home Page KalAajKal.com
 Advertise your Business Here     
Browse  |   Placement Papers  |   Company  |   Code Snippets  |   Certifications  |   Visa Questions
Post Question  |   Post Answer  |   My Panel  |   Search  |   Articles  |   Topics  |   ERRORS new
   Refer this Site  Refer This Site to Your Friends  Site Map  Bookmark this Site  Set it as your HomePage  Contact Us     Login  |  Sign Up                      
info       Did you received any Funny E-Mails from your Friends and like to share with rest of our friends? Yeah!! you can post that stuff   HERE
Google
 
Categories >> Aptitude-Questions >> Puzzles
 
 
 
Question
Consider a number 235, where last digit is the sum of first 
two digits i.e. 2 + 3 = 5. 

How many such 3-digit numbers are there?
 Question Submitted By :: Guest
I also faced this Question!!     Rank Answer Posted By  
 
Answer
There are 45 different 3-digit numbers. 

The last digit can not be 0. 

If the last digit is 1, the only possible number is 101. 
(Note that 011 is not a 3-digit number) 

If the last digit is 2, the possible numbers are 202 and 
112. 

If the last digit is 3, the possible numbers are 303, 213 
and 123. 

If the last digit is 4, the possible numbers are 404, 314, 
224 and 134. 

If the last digit is 5, the possible numbers are 505, 415, 
325, 235 and 145. 

Note the pattern here - If the last digit is 1, there is 
only one number. If the last digit is 2, there are two 
numbers. If the last digit is 3, there are three numbers. 
If the last digit is 4, there are four numbers. If the last 
digit is 5, there are five numbers. And so on..... 

Thus, total numbers are 
1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 = 45 
 
0
Guest
 
View All Answers
 
 
 
 
 
   
Copyright Policy  |  Terms of Service  |  Help  |  Site Map 1  |  Articles  |  Site Map  |   Site Map  |  Contact Us interview questions urls   External Links 
   
Copyright © 2007  ALLInterview.com.  All Rights Reserved.

ALLInterview.com   ::  Forum9.com   ::  KalAajKal.com