x-OR the number with 0x02.

Iteration heirarchi is means looping.
In c++ everything is based on Object.Object is the reference
to the class.

Implementing virtual mechanism to handle messages would 
have made the message dispatch process very expensive as
* every class of any window type would have a huge virtual 
function dispatch table associated with it.

Instead having static array of function pointers ensures 
only one copy for a given class

In MFC we have lot of base classes those are having so many
virtual functions. For each class one virtual table will be
created. This will consume lot of memory and our application
performance will go down. This is the only reason MFC is not
using virtual function for message mapping.

main()
{
int num=0,sum=0,k=0;
pirntf("enter the number\n");
scanf("%d",num);
   while(num!=0);
    {
      k=num%10;
      sum=sum+k;
      num=num/10;
    }
printf("%d",sum);
}

void main()
{
long int num;
int sum=0,temp;
clrscr();
printf("Enter the numbe\n");
scanf("%ld",&num);
while(num!=0)
{
temp=num%10;
sum=sum+temp;
num=num/10;
}
printf("%d",sum);
getch();
}


#include<stdio.h>
#include<conio.h>
void main()
{
int i,j;
scanf("%d",&i);
if((i%9)==0)
printf("The sum of digit is 9");
else
{
j=i%9;
printf("%d",j);
}
}

#include<stdio.h>
void main()
{
int i,j;
scanf("%d",&i);
if((i%9)==0)
printf("The sum of digit is 9");
else
{
j=i%9;
printf("%d",j);
}
}

//the above will print result as 6 if given as 12345 since
1+2+3+4+5=15 and proceeding 1+5 we get as 6.....
is this an apt answer...

#include<stdio.h>
#include<conio.h>
void main()
{
int i,j,sum=0;
clrscr();
printf("\n enter a number",i);
scanf("%d",&i);

while(i<=0)
  {
    j=i%10;
    sum=sum+j;
    i=i/10;
   }
printf("\n the sum of the digits 
        are:%d\n");
getch();
}

NO,if the values of a&b are 10,20 respectively., Then
   a=a+b becomes "a=30"
   b=a-b becomes  b=30-20  i.e., "b=10"
   a=a-b gives  a=30-10    i.e., "a=20"

provided a+b is between the int minimum and int maximum

so the answer is no.

NO 
Means we can give diff values give different answer.
like
we can give a=80,b=100
a=180,b=20,a=20

Sorry, it does nott.. :-)
it works proper..

no,result will depend on the values of a nd b

1) class aclass{public:int x;}

class aClass{public:int x;}

1) class aClass{public:int x;}

I think char x=12 is also not valid

Because 1.maximum length of the character can be 1 character 
2.It should enclosed within single inverted commas, like
'1',or 'a'.

3.both are works well.

3) They both work

2) false

It depends upon the variable type. Ex: if the variable is
declared as unsigned int then if we increment the value will
not become negative.

It will not become negative if we use unsign data type.

after a limit of the variable ,it becomes -ve.
for ex:-
#include<stdio.h>
void main()
int i;
if(i<=32767)
{
printf("%d",i);
i++;
}
}after printing 1 to 32767,it tries to become 32768 which is
outside the limit,so it goes to the other side and become
-32768 and loops become indefinite.

1)0

May be the options are not correct. Do u feel that 0 is
ascii zero or numeric zero. If numeric zero, then the answer
is wrong. Every string will be terminated with the special
character '/0'.

The answer is '\0' not /0