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Categories >> ERRORS
 
  C-C++-Errors (62)  DotNet-Errors (14)  Scripts-Errors (55)
 


 

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Question
when i save float data value 11.22 but this see in table 
11.220000004758456 type ? how to save only two decimal point.
Rank Answer Posted By  
 Question Submitted By :: Rake$h
I also faced this Question!!   ALL Interview .com
Answer
if u put 11.22 in a variable x, try this :

x=11.22;
printf("%2.2f",x);

2.2f specifies that ,it will print exactly 2 digits to the 
left of decimal point and 2 digits to the right of the decimal 
point.You can use any number according to ur requirement ,like 
(%x.yf).
 
0
Guest
 
 
Question
osgelvaitre arrange it which make 1 romantic 
word
Rank Answer Posted By  
 Question Submitted By :: Rahul
I also faced this Question!!   ALL Interview .com
Answer
Love is Great
 
0
Akshay Jain
 
 
Question
Write a C program to enter 10 integer numbers through one variable and count how many of them are even using while loop ?
Rank Answer Posted By  
 Question Submitted By :: Jayant.champ
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Answer
#include<stdio.h>
#include<conio.h>

void main()
{
int var;
int count=0;
int n=0;
clrscr();
while(n<10)
{
printf("Enter the number:");
scanf("%d",&var);
if(var%2 == 0)
{
count++;
n++;
}
else
{
n++;
continue;
}
}
printf("Even numbers present:%d",count);
getch();
}
 
0
Nipun
 
 
 
Question
Write a program to accept two strings of Odd lengths. Then 
take all odd characters from one string and even characters 
from the other and concatenate and produce a string.
Rank Answer Posted By  
 Question Submitted By :: Mani
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Answer
#include<stdio.h>
void main()
{
char *str1[10],*str2[10],str3[10],str[4];
boolean check1,check2;
int i=0,j=1;
do
printf("enter the first string of odd length");
scanf("%s",str1);
printf("enter the second string of odd length");
scanf("%s",str2);
check1=testlen(&str1);
check2=testlen(&str2);
}
while(check1!=true && check2!=true);

while( *str1!='/o' || *str2!='/o')
{
if(str1[i]!='/o)
str3[i]=str1[i];

if(str2[i]!='/o)
str3[i+1]=str2[i];

i+=2;
}

while( *str1!='/o' || *str2!='/o')
{
if(str1[j]!='/o)
str4[j]=str1[j];

if(str2[j]!='/o)
str4[j+1]=str2[j];

i+=2;
}
printf("The value of string1 is %s",str1);
printf("The value of string1 is %s",str2);
printf("The value of string1 is %s",str3);
printf("The value of string1 is %s",str4);

}

boolean testlen(char *c) //function
{
int count;
while(*c++!='/o')
count++;
if(count%2!=0)
return true;
else
return false;
}

 
0
Mani
 
 
Question
what is wrong with this insert into code?
vb 2008 say that there is a syntax error but i believe there is nothing..

cmd.CommandText = " INSERT INTO account1(username, password, lname, fname, mi) VALUES('" & Me.TextBox4.Text & "','" & Me.TextBox5.Text & "','" & Me.TextBox1.Text & "','" & Me.TextBox2.Text & "','" & Me.TextBox3.Text & "')"
                cmd.ExecuteNonQuery()
Rank Answer Posted By  
 Question Submitted By :: Asloversgo_03
I also faced this Question!!   ALL Interview .com
Answer
" INSERT INTO account1(username, password, lname, fname, mi) VALUES('" + Me.TextBox4.Text + "','"+ Me.TextBox5.Text + "','" + Me.TextBox1.Text + "','" + Me.TextBox2.Text + "','" + Me.TextBox3.Text + "')"
 
0
Kk
 
 
 
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