1.Goto file<new project<select setup and deployment in the 
template
2.Add your project by right click the project that u newly 
created(In Solution Explorer)
3.Add Project ouput and localised resources by right 
clicking the existing project in solution explorer
4.Finally build the project 
(or)

Take a Setup project from Visual Studio Deployment 
Projects. By default you will get. 
File System on Target Machine
Different Editors in Setup project

1. File System on Target Machine.
2. Registry on Target Machine
3. File Types
4. User Interface
5. Custom Actions
6. Launch Conditions

For inti As Integer = 0 To ComboBox1.Items.Count - 1
      For intj As Integer = 0 To ComboBox2.Items.Count - 1
          If ComboBox1.Items(inti).ToString =  
ComboBox2.Items(intj).ToString Then
             MessageBox.Show(ComboBox1.Items(inti))
          End If
      Next
  Next

For inti As Integer = 0 To ComboBox1.Items.Count 
      For intj As Integer = 0 To ComboBox2.Items.Count 
          If ComboBox1.Items(inti).ToString =  
ComboBox2.Items(intj).ToString Then
             MessageBox.Show(ComboBox1.Items(inti))
          End If
      Next
  Next


The answer should be modified. The loop should not go upto 
the count-1 but should go upto count. Rest all is OK.

/* C# Version */

for (int i=0; i<= ComboBox1.Items.Count)
  {
    for(int j=0 ; j<= ComboBox2.Items.count)
       {
         if (ComboBox1.Items[i].Text == ComboBox2.Items
[j].Text)
            MessageBox.Show(Items[i].Text);
       }
   }

Compare the values in both the comboboxes :


if(comboBox1.Text == comboBox2.Text)
{
    MessageBox.Show(comboBox1.Text);

}

bool found = false;
string item = string.Empty;
foreach (string item1 in comboBox1.Items)
{
	foreach (string item2 in comboBox2.Items)
	if (item1 == item2)
	{
		item = item1;
		found = true;
		break;
	}
	if (found) break;
}
MessageBox.Show(found ? item : "Not found");

first time insetr five columns but two columns are empty 
value thats null value when we click another button update 
query is used insert remaining columns (where condition 
filled columns value)

1st button
Insert into table names (@column1,@column2,@column3,'','')
2nd button
update tablename set column4=@column4,column5=@column5 
where column1=@column1 and column2=@column2 and 
column3=@column3
hope it will help

Its very easy. 
1-Take a barcode font like we used Arial, Time new Roman
2-Install this font at window fonts directory
3-Use Steric (*) at both ends of a field of Report with the 
help of double/single commas 
4.Change this field Font Like from Time new roman to 
Barcode font
e.g Bar is field that contain digit from 1 to 8 as shown 
below
  *12345678*
After changing font these digit were converted into Black 
Lines mean barcode
|||||||||||||||

5-Take print of barcode and enjoy.

If you feel any problem then email me at 
salmansahb@hotmail.com and i will furhter send you font or 
report.

Hi Sulman,

I actually didn't get how to install it in Windows forms 
and how to actually get it from there. Can you tell me in 
detail. 
It will be greatful to you.

insert into <tablename> values (Parm1,parm2....)

<base target="_self"> is the only available fix. You can
delete all the cache & offline files from your browser.

Validate

In List Box we have to choose one of the option from the 
drop down list 
In Combo just like radio button we have to choose any one

ListBox is used to select one item out of diffenrent we 
have.
But
ComboBox is used to enter an item at run time.

in ListBox u can select multiple items.
but in Combo box u can select only one item.

The listbox control is used to display a list of items to a 
user.
Combobox control is used to display a drop- down list of 
items . It is a combination of a text box in which a user 
enter an items,and a drop-downlist from which the user 
selects an item.

In listbox we can select more than one item.
but in case of combobox we dont have that chance,we have to 
select only one item from the list of items.

1) Combo Box:												
a. User should be able to enter text in it.												
b. Pressing the arrow should give list of options available
to the user. List can be scrollable but user should not be
able to type in.												
c. Pressing Ctrl-F4 should open the list box.												
d. Pressing a letter should bring the first item in the list
starting with the same letter.												
e. Items should be in alphabetical
order in any list.												
f. Selected item should be displayed on the list.												
g. There should be only one blank space in the
dropdown list.												
												
2) List Boxes:												
a. Should allow single select, either by mouse or
arrow keys.												
b. Pressing any letter should take you to the first element
starting with that letter												
c. If there are view/open button, double clicking on icon
should be mapped to these behaviour.												
d. Make sure that all the data can be seen using
scroll bar.