You will have to use a structure or an array and then return
a pointer to the structure/array.

using call by refernce

use call by refrance..-> pointers.

using if else statement
for example
int fun()
{
if(cond1)
return var1;
else
return var2;

}

string f()
{
   return "a multiple value"; 
}

:) if this a trick question ...

MailMessage message = new MailMessage ();
        message.From = <email>;
        message.To = <email>;
        message.Subject = "Scheduled Power Outage";
        message.Body = "Our servers will be down tonight.";
        SmtpMail.SmtpServer = "localhost";
        SmtpMail.Send (message);


MailMessage and SmtpMail are classes defined in the .NET 
Framework Class Library's  System.Web.Mail namespace.

Due to a security change made to ASP.NET just before it 
shipped,  you need to set SmtpMail's SmtpServer property 
to "localhost" even though "localhost" is  the default.

In addition, you must use the IIS configuration applet to 
enable localhost  (127.0.0.1) to relay messages through the 
local SMTP service.

OR ANOTHER EASY METHOD IS TO WRITE THE pOST METHOD IN THE 
html page or design page .. may b this could be one more 
soln.????

protected void btnsubmit_Click(object sender, EventArgs e
{
System.Net.Mail.MailMessage msg = new
System.Net.Mail.MailMessage(txtfrom.Text, txtname.Text,
txtSubject.Text, txtmessage.Text);

        System.Net.Mail.SmtpClient mysmtp = new
SmtpClient("192.168.1.80");
        try
        {
            mysmtp.Send(msg);
            lblmsg.Text = "mail sent";
        }
        catch (Exception ex)
        {
            lblmsg.Text = ex.Message;
        }
    }
}

protected void btnsubmit_Click(object sender, EventArgs e
{
System.Net.Mail.MailMessage msg = new
System.Net.Mail.MailMessage(txtfrom.Text, txtname.Text,
txtSubject.Text, txtmessage.Text);

        System.Net.Mail.SmtpClient mysmtp = new
SmtpClient("192.168.1.80");
        try
        {
            mysmtp.Send(msg);
            lblmsg.Text = "mail sent";
        }
        catch (Exception ex)
        {
            lblmsg.Text = ex.Message;
        }
    }
}

OR

MailMessage message = new MailMessage ();
        message.From = <email>;
        message.To = <email>;
        message.Subject = "Scheduled Power Outage";
        message.Body = "Our servers will be down tonight.";
        SmtpMail.SmtpServer = "localhost";
        SmtpMail.Send (message);


MailMessage and SmtpMail are classes defined in the .NET 
Framework Class Library's  System.Web.Mail namespace.

Import system.net.mail

Protected sub button_click(ByVal sender as object, ByVal e
as system.EventArgs)handles button.click

dim smtp As New SmtpClient()
smtp.send(New
MailMessage(txtfrom.text,txtto.text,txtsubject.text,txtbody.text))
label.text="Message sent"
End sub

System.Web.Mail.MailMessage obMessage = new 
System.Web.Mail.MailMessage();
obMessage.To = "Receiver@gmail.com";           
obMessage.From = "sender@gmail.com";
obMessage.Subject = strSubject;
obMessage.Body = "Hi! this is the way to send mail;
obMessage.BodyFormat = HTMl;
try
   {
 SmtpMail.SmtpServer = "";
SmtpMail.Send(obMessage);
 bRet = true;
    }
catch (System.Web.HttpException exhttp)
    {
       Trace.Write("Error sending mail " + exhttp.Message);
  }

asp.net is a web based application,so asp.net can send e-
mail from an asp.net application

mailmessage obmail = new mailmessage();
obmail.To= "Dummy@gmail.com";
obmail.from= "sender@gmail.com";
obmail.Subject="Mail sending through web";
obmail.body="Deascription";
try
{
smtp.server="";
smtp.send(obmail);
}
catch(System.Web.HttpException exhttp)
{
trace.write("error sending mail " +exhttp.message);
}

protected void btn_submit_Click(object sender, EventArgs e)
    {
        try
        {
            string rd = "";
            MailMessage mM = new MailMessage();
            mM.From = new MailAddress(Email.Value);
            mM.To.Add("<email>");
            mM.Subject = title.Value;
            if (Radio1.Checked)
            {
                rd = Radio1.Value;
            }
            else
            {
                rd = Radio2.Value;
            }
            mM.Body = rd + "<br>" + name.Value + "<br>" +
title.value + "<br>" + Company.Value + "<br>" + Email.Value
+ "<br>" + url.Value + "<br>" + Comment.Value;
            mM.IsBodyHtml = true;
            mM.Priority = MailPriority.High;
            SmtpClient smtp = new
SmtpClient("smtp.gmail.com", 587);
            smtp.EnableSsl = true;
            smtp.UseDefaultCredentials = false;
            smtp.Credentials = new
NetworkCredential("username", "P@ssword"); //From user
credentails 
            smtp.DeliveryMethod = SmtpDeliveryMethod.Network;
            smtp.Send(mM);
            AlertBox("Mail Send successfully");
        }
        catch 
        {
            AlertBox("Mail Send Failed");
        }
    }

BY USING PRINTF AND SCANF

Using a rectangle(int,int,int,int)function of c graphics.

using include<graphic.h>

using ASCII codes and then using goto statements

using rectangle(int,int,int,int)
               <left,top,right,bottom>
it is a function in graphics.h

USING rectangle(int,int,int,int)
it is a function in graphics.h

including graphics.h
then initialising graphics system using initgraph
and using the function rectangle(int left,int top,int 
right,int bottom)

no answer

using rectangle(int right,int top,int left,int bottom) in 
graphics.h

first include the graphics.h file 
thus you can use the rectangle funtion give the proper 
parameters and the wor is done

Divide by Zero.

BY using #include<graphics.h>
we can draw rectangle.
The syntax is rectangle(int ,int ,int ,int)
{left,top,right,bottom}

printf("____________________");
printf("\n|\t\t|\n|\t\t|\n|\t\t|\n|\t\t|");
printf("____________________");

    by this way i think can be possible,though some 
adjustment may required...as per size of VDU.As per my 
opinion intervier asked for this answer....as C graphics is 
not so popularly used.
     Pardon me if i'm wrong & can also mail to me.

line(x1,y1,x2,y1)
line(x1,y2,x2,y2)
line(x1,y1,x1,y2)
line(x2,y1,x2,y2)

/*  simple.c
    example 1.0
*/
#include<graphics.h>
#include<conio.h>

void main()
{
    int gd=DETECT, gm;

    initgraph(&gd, &gm, "c:\\turboc3\\bgi " );
    rectangle(200,50,350,150); 

    getch();
    closegraph();
}

/*  simple.c
    example 1.0
*/
#include<graphics.h>
#include<conio.h>

void main()
{
    int gd=DETECT, gm;

    initgraph(&gd, &gm, "c:\\turboc3\\bgi " );
    rectangle(200,50,350,150); 

    getch();
    closegraph();
}

#include<stdio.h>
#include<conio.h>
#include<graphics.h>
void main()
{
int driver,mode;
driver=DETECT;
initgraph(&driver,&mode,"c:\\tc\\bgi");
rectangle(100,100,250,250);
getche();
closegraph();
}

line(x1,y1,x2,y1)
line(x1,y2,x2,y2)
line(x1,y1,x1,y2)
line(x2,y1,x2,y2)

initgraph(&gd, &gm, "c:\\turboc3\\bgi " );
    rectangle(200,50,350,150);

to use follows

rect(x1,y1.x2,y2);

using turboc2 editor

using pen & scale

First we insert the graphics mode into your complier,and we
use the function rectangle(); in the rectangle function we
specified the length and breath,and we also specified where
the place in screen the rectangle is drawn.

include graphics.h

rectangle(int,int,int,int)

closegraph()

include the header file graphics.h 
use the built in function rect(x1,y1,x2,y2)
such that (x1,y1) and (x2,y2) are the coordinates

There are lot of third party API's availbale. Please try 
below one available in Jakarta site
Apache POI - HWPF - Java API to Handle Microsoft Word Files

#include"stdio.h"
#include"stdlib.h"

int reverse(char *string, char delimiter)
{
  char *src, *dest;
  char *temp = string;

  while( *temp )
  {
    if (*temp == delimiter)
    {
      temp++;
      continue;
    }

    src=dest=temp;
    while ( (*(dest+1) != delimiter) &&
            ( *(dest+1) != '\0' )) dest++;

            //( *(dest+1) != '\n' ) &&
    temp=dest+1;
    while( dest > src )
    {
      char tmp = *dest;
      //*dest -- = *src;
      *dest = *dest-- *src;
      //*src++=tmp;
      *src = *src++ tmp;
    }
  }
  return 0;
}

int main()
{
    char name[] = "vinod kumar dhochak";
    printf("%s\n",name);
    reverse(name,' '); /* space as delimiter,Reverse Words 
*/
    printf("%s\n",name);
    reverse(name,'\n'); /* Reverse Complete Sentence */
    printf("%s\n",name);
}

#include<iostream>
#include<vector>
using namespace std;
int main()
{
    char str[]="rahul shandilya is going";
    
    string ans;
    int n=0;
    while(str[n]!='\0')
         n++;   
         //cout<<n;  
        bool flag=true;     
   for(int i=n-1;i>=0;i--)
   {
          if(str[i]==' ')
          {
                       int m=i+1;
                      // cout<<m<<" ";
                       string temp;
                       while(str[m]!=' ' && m<n)
                       { 
                                       temp+=str[m];
                                       m++;
                       }
                       //cout<<m<<" ";
                       if(flag)
                       {
                               ans+=temp;
                               flag=false;
                               continue;
                       }
                       if(flag==false)
                       {
                                      ans+=' ';
                                      ans+=temp;
                       }
          } 
   }
    
   cout<<ans; 
    system("pause");
    return 0;
}
//tell me if there is a batter way to do it,i dont think my 
//solution is efficent

/*complexity-2n..check d prog.  */

#include<iostream.h>
#include<string.h>
#include<stdio.h>


void rev_word(char str[20],int m,int n)
{
int i,l,k;
k=n-m+1;
if(k%2==0)
l=(k/2-1);
else
l=k/2;
k=n;
for(i=m;i<=m+l;i++)
{ count++;
char t=str[i];
str[i]=str[k];
str[k]=t;
k--;
}
}
int main()
{
char str[100];
int i,j=0;
cout<<"\n\nenter string:";
gets(str);

rev_word(str,0,strlen(str)-1);


for(i=0;i<=strlen(str);i++)
{    count++;
if(str[i]==' '||str[i]=='\0')
{
rev_word(str,j,i-1);
j=i;
while(str[j]==' ')
j++;
i=j;
}
}
cout<<"\n\nsentence with order of words reversed is:";
cout<<str;
return 0;
}

#include<stdio.h>
main()
{
	int i=0,j=0,start=0,end=0,len,w_len;
	char temp;
	char str[]="Papa Kehte HAIN bada naam karega";
	printf("Before reversing the words string is %s \n",str);
	len=strlen(str);
	for(i=0,j=len-1;i<j;i++,j--)
	{
		temp=str[j];
		str[j]=str[i];
		str[i]=temp;
	}
	for(i=0,j=0;str[i]!=0;)
	{
		i=j;
		for(;str[i]!=' '&& i<len;)
			i++;
		w_len=(i-j)-1;
		
		for(start=j,end=(start+w_len);start<end;start++,end--)
		{
			temp=str[start];
			str[start]=str[end];
			str[end]=temp;
		}
		j=i+1;
	}
	printf("After  reversing the words string is %s \n",str);
}

$conn = mysql_connect("localhost","root","");
  mysql_select_db("database_name",$conn);  // Connection....

  if($hh){

     $res = mysql_query("insert into `table`(`all 
paramaeters of table`)values('','','')");

  }
     $res1 = mysql_query("select * from `table`"); 
 
                  // Insert Module....

<?php
//var_dump($_POST);
	//die();
$link=mysql_connect("localhost","root","");
$db=mysql_select_db("emp",$link);
$id=$_POST['id'];
$name=$_POST['name'];
$age=$_POST['age'];
$phone=$_POST['phone'];
$salary=$_POST['salary'];
$address=$_POST['address'];


$query="insert into db(id,name,age,phone,salary,address)
values
('".$id."','".$name."','".$age."','".$phone."','".$salary."'
,'".$address."')";
//echo $query;
mysql_query($query);
echo "<B></B>DATA ADDED SUCCESSFULLY<B></B>";
?>

To
Connect="$dblink=mysql_connect("127.0.0.1","mediamagick","mediamagick");
$db_conn=mysql_select_db("mediamagick_italy",$dblink)or
die("could not connect");"
And To Insert = "Select (Field Names) values (values to
insert )";

<?php
->connection parts-------
mysql_connect("<webser-name>","user-name","password-name");
mysql_select_db("<database-name>");
->insertion parts--------
$r=mysql_query("insert into <table-name> values(fild 
name)");
if($r)
{
print "<h1>insert successfully";
}
else
{
print"<h1>insert not successfully";
}

#include<iostream.h>
#include<conio.h>
int leap(int y)
{
if(y%4==0&&y%100!=0||y%400==0)
return 1;
else
return 0;
}
main()
{
int d,m,y,i,rem;
int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
long int days=0;
clrscr();
cout<<"enter date in dd/mm/yyyy format:";
cin>>d>>m>>y;
for(i=1;i<y;i++)
if(leap(i))
days+=366;
else
days+=365;
for(i=1;i<m;i++)
if(leap(y)&&i==2)
days+=29;
else
days+=a[i-1];
days+=d;
rem=days%7;
switch(rem)
{case 1:cout<<"monday";
break;
case 2:cout<<"tuesday";
break;
case 3:cout<<"wedday";
break;
case 4:cout<<"thursday";
break;
case 5:cout<<"friday";
break;
case 6:cout<<"saturday";
break;
case 0:cout<<"sunday";

}
getch();
return 0;
}

Hey buddy wrong program....!!! 

if you check with DOB : 16/4/1985 OR 16/04/1985

its showing Friday...

But if you check then right answer should be Tuesday ...

No..it's giving Tuesday only..U enter 16 4 1985 n press enter.
It will show Tuesday only..Logic is correct.I made a mistake
by telling to enter date in dd/mm/yyyy format..but u just
enter date in dd mm yyyy format(space between dd,mm and
yyyy)..u will get correct ans.

                                             Raghuram.A

Hi Raghu, thanks for your program.
can you try 29th of feb 1983 (29/02/1983). Actually such a 
date is not present. But gives Tuesday.
May be you like to correct it.

Well..Abraham..I am not checking for invalid dates in that
program.
Here is the program that u want..

#include<iostream.h>
#include<conio.h>
#include<stdio.h>

int leap(int y)
{
if(y%4==0&&y%100!=0||y%400==0)
return 1;
else
return 0;
}


int valid(int dd,int mm,int yy)
{
if(dd>31||dd<1||mm>12||mm<1||yy<0)
return 0;
if(mm<8)
if(mm%2==0&&dd>30)
return 0;
if(mm>=8)
if(mm%2!=0&&dd>30)
return 0;
if(mm==2)
{
if(yy%4==0&&dd>29)
return 0;
else
if(yy%4!=0&&dd>28)
return 0;
}
return 1;
}
main()
{
int d,m,y,i,rem;
int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
long int days=0;
clrscr();
cout<<"enter date in dd m yyyy format:";
scanf("%d %d %d",&d,&m,&y);
if(!valid(d,m,y))
{
cout<<"\nInvalid date";
getch();
return 0;
}

for(i=1;i<y;i++)
if(leap(i))
days+=366;
else
days+=365;
for(i=1;i<m;i++)
if(leap(y)&&i==2)
days+=29;
else
days+=a[i-1];
days+=d;
rem=days%7;
switch(rem)
{
case 1:cout<<"monday";
break;
case 2:cout<<"tuesday";
break;
case 3:cout<<"wedday";
break;
case 4:cout<<"thursday";
break;
case 5:cout<<"friday";
break;
case 6:cout<<"saturday";
break;
case 0:cout<<"sunday";
}
getch();
return 0;
}

pleasse refer calender book....

if u feel difficult to find your day of your date of birth
call me...i will help u!
                         by prof.muthu  M.C.A PHD 
                         PH:9962940220

@Raghu..

good job.. :-)
thanks for the code.. :-)

using date structures

who is this moron prof.muthu....y the hell r u writing such
nonsense...we all know to solve by ur methods..jus stop
writing such things or GO TO HELL.

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void main()
{
	char path[100];
	cout<<"Enter the path of directory::";
	cin.getline(path,100);
	system("cd path");
	system("dir");
} // In windows
  // For linux change dir to ls.

main()
{
	char path[100];
	printf("Enter the path of directory:");
	scanf("%s",path);
	system("cd path");
	system("ls");
}

please write the correct program with output...
 
                               by prof.muthu m.c.a phd etc..
                               ph:9962940220

int main(int argc, char * argv[])
{
    //argc has count of no of arguments on command line.
    // argv[] contains array of strings seperated by space.
    // so argv[1] will give u, second argument, with first
    // argument being ur ./a.out(in unix)/test.exe(in win)
    // so this way u can access CL args.

    // ur code.
}

int main(int argc,char *argv[])
{
	int i;
	for(i=0;i<argc;i++)
	cout<<argv[i];
}

argc is nothing but Argument Count
argv is nothing Argument Vector (or) Argument Value which 
is array of Strings.

The first argument to the Command line is always the 
Program Name. 

argc contains no. of Arguments that it passed including the 
Program Name.So Leave the 1st Argument,

int i;
for(i=1;i<=argc;i++)
cout<<argv[i];

By using -->
   int main(int argc, char * argv[])

In this statement the variable argc holds the at least one 
argument of type int , the name of the file it self first 
argument and *argv[] is array of char which takes the name 
of file.......
      If any correction plz E-mail me ...
                   Bye

Make array of values and return the array address as long. 
Now using pointer traverse through the value.

you can return multiple values from the function by using 
mechanism  called "call-by-reference".
for example:
  
void main()
 {
    int area,*circumference;
    area=function(area,circumference);
    cout<<"the area is "<<area;
    cout<<"the circumference is"<<circumference;
 }
int function(int a,int *b)
 {
    a=12;
    int temp=a*3;
    b=&temp;
    return a;
 }

// this is just an example............


// you can also use array and return the adress of the 
array in the main and can use to traverse the entire array 
and return multiple values from function.

Make array of values and return the array address as long. 
simple example:
void main()
{
 int a[10],i,n;
 int *new_value_array;
 printf("\n Enter how many number you want to enter? ");
 scanf("%d",&n);
 for(i=0;i<n;i++)
 sacnf("%d",&a[i]);
 printf("\n old value of the array is:");
 for(i=0;i<n;i++)
 printf("\t%d",a[i]);
 new_value_array = array_modify(a,n);
 printf("\n new value of the array is: \n");   
 for(i=0;i<n;i++)
 printf("\t%d",*(new_value_array+i));
 getch();
}
 int *array_modify(int a[10],int n)
{
 int i;
 for(i=0;i<n;i++)
 a[i]=a[i]*4;
 return(a);
}

Multiple values can be returned from a function,
using the call by refrance method.

in this method, we pass pointers as the argument to the 
funtion..

#include<stdio.h>
void main()
{
   int number;
    printf("|n enter a  number");
    scanf("%d",&number);
    int twopower(int);
   printf("\n the given number is ");
}
 int twopower(int num)
   {
       while((num & -num)==num)
          return(1);
        printf("|n yes power of two");
}

#define ISPOW2(x) ( (x + (x-1) ) == (x<<1 + 1) )

main()
{
int a;
scanf("%d",&a);
if((a+(a-1))==((a<<1)-1))
printf("it is powers of 2");
else
printf("not powers of 2");
}

#include<stdio.h>

main()
{
int a;
scanf("%d",&a);
if (a&1) 
printf ("POWER off 2");
printf ("NOT power of 2");
}

if (x & (x-1))  // false only if x is a power of 2

# include <stdio.h>

void main()
{
       int n;
       scanf("%d",&n);
       if( n & (n-1) )
           printf("Not a Power of 2");
       else
           printf("Power of 2");
}

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

bool isPowerOf2(int number){
	if ( number > 0 )
		return (number & (number-1)) == 0;
	
	if (number == 0)
		return false;
	
	if (isPowerOf2(-number)){
		int count=0;
		while ( !(number & 1)) {
			++count;
			number >>= 1;
		}
		if (fmod(count,2))
			return true;
		else
			return false;
	}
	return false;
}

int main(void) {
	for(int i=-1027; i<1025; ++i){
		if (isPowerOf2(i) )
			printf("%d\n", i);
	}
	
	return EXIT_SUCCESS;
}

#include<stdio.h>

void main()
{
int a,i;
scanf("%d",&a);

for( i = 0; a != 0; a = a >> 1)
	if( a & 0x01 )
		i++;
if( i == 1 )
printf ("POWER off 2");
else
printf (" Not power of 2");
}

I think
if (x & (x-1))   wont work when number is negative.

simple ! 
create a loop by main()

.i.e call main(previous_num) from main. 

till break char is hit.

plz explain above answer ......

#include<stdio.h>
#include<conio.h>
#include<stdlib.h>
void main()
{
 int i=0,n,x;
 scanf("%d",&n);
 label1:
 {
  printf("%d",i);
  i++;
  x=i<n?i:0;
  exit(x);
  continue;
 }
 getch();
}

main()
{
int n;
printf("enter limit:");
scanf("%i",&n);
print(n);
}

print(int n)
{
n>0?print(n-1):printf("");
printf("\n%d",n);
}

//Simple.use recursion!
#include<stdio.h>
int f(int i,int n)
{
i<=n&&printf("\t%d",i)&&f(++i,n);
return 1;
}
main()
{
f(1,100);
return 0;
}

main()
{
static int i;
printf("%d \n",i++);
main();	
}

//To print 1-50 without using any loops or condition statement
main()
{
static int i;
printf("%d \n",i++);
(i%51)&&main();	
}

void main()
{
if(printf("semicolon")){}
if(printf(getch())){}
}

void main()
{
    while(!printf("\nHello World"))
}

Answer #1 and #2 are wrong. They dont work on Turbo C. If
anybody knows the write answer please email me the code.