All the members of the structure can be accessed at
once,where as in an union only one member can be used at a time.
Another important difference is in the size allocated to a
structure and an union.
for eg:
struct example
{
  int integer;
  float floating_numbers;
}
the size allocated here is sizeof(int)+sizeof(float);
where as in an union
union example
{
  int integer;
  float floating_numbers;
}
size allocated is the size of the highest member.
so size is=sizeof(float);

please post the answer...



thanks and regards
kiran.y

link list i think..

findloop(struct node *start)
{
 struct node *ptr,*ptr1;
start=ptr;

 while(ptr!=NULL)
{
  ptr1=ptr->next;
  
  while(ptr1!=NULL)
  {
     if(ptr1->link==ptr->link)
     {
        printf("\nLoop found at %d node",ptr->data);
        exit(0);
       }
    ptr1=ptr1->link;
}
ptr=ptr->link;
}
printf("\nNo Loop found in list");
}

BOOL findloop(struct node *start)
{
 struct node *ptr,*ptr1;
 ptr=start;
 ptr1= start->next;
 while(ptr!=NULL && ptr->next!=null && ptr1->next!=null && 
ptr1->next->next!=null)
   {
     if(ptr==ptr1)
          return FALSE;
     ptr=ptr->next;
     ptr1=ptr1->next->next;
   }
  return TRUE;
}

solution for 1st case:
Given:(x1,y1),(x2,y2),(x3,y3),the co-ordinates of the
vertices of the triangle.
 Let (xx,yy) be the pt to be located.
 Find the equations of the lines {(x1,y1),(x2,y2)} and
{(x1,y1)(x3,y3)} using the formula 
((y-y1)/(y2-y1))=((x-x1)/(x2-x1))

 Now substitute the y value  in the 2 equations got. You 'll
be getting the x limits. If the given x value lies within
the limits you have found,the given pt is within the
triangle or else it is not.

#include<stdio.h>
void main()
{
char names[10][20];
int a[10][2],n;
printf(":enter the number of students :");
scanf("%d",&n);
printf("enter the names and marks");
  for(int i=0;i<n;i++)
{
scanf("%s",names[i]);
scanf('%d",&a[i]);
}
printf("the passed students are :\n");
for(int i=0;i<n;i++)
{
  if(a[i]>=35)
{
printf("%s",names[i]);
}
}
getch();
}