computing language

compiler should not make any assumption about the variable 
which declared as volatile.

In c u can create variable with name new and delete but not
in c++.

if a structure tag is a datatype of a variable or data
member then it is known as a self referential structure.


for ex
template <class t>

  struct node
   { 
    t data;
    node *link;//here link is a variable which contains data
type of structuretag ie node
    }

whenever a structure is been pointed by the same structure
pointer which is the member of the same structure is called
as self referential structure....


thank u

main()
{
int x,y;
sf("%d,%d",&x,&y);
if(x^y)
pf("not equal");
else
pf("equal");
}

at the level of the language as a storage class persistence 
is defined on ... A program written in C is passed through 
a precompilation phase in which the statements related to 
persistence are converted into their corresponding storage 
system calls.

5 20 1

4,4,1
coz we shift the bit as 5=101  now shift two bit to right as
101>>2=001
now
2<<001=100
noe x=4
printf execute from right to left so ans is 4,4,1

4 4 1  is the output....

here the operation of STACK involves.... for these kind of statements (ie) statements having multiple values to get printed it is used..... so the very first element that goes inside stack is x , then x<<2 , then x>>2... so from the TOP it will be operated....
and print as the order given in printf statement..... :) 

thank u

num ^ (1 << n)

num=num ^ (1<<(n-1));

void Traverse(Node *t)
{
   if(NULL == t)
       return;

   //in-order traversing
   Traverse(t->left);
   printf("%d",t->data);
   Traverse(t->right);

  //pre-order
  printf("%d",t->data);
  Traverse(t->left);
  Traverse(t->right);

  //post order
  Traverse(t->left);
  Traverse(t->right);
  printf("%d",t->data);
}

1. returning address of a local variable.
2. wrong parameter passed to strcpy()

In this question ,two wrong thins ----
1.this is an array of char pointer so use 
  strcy(text[no.],"Hello World");

2.
 we are copying a string without allocating memory to pointer . This is bug code .

correct solution :----

char *string()
{
   char *text[20];
   text[0]=malloc(20*sizeof (char));
   strcpy(text,"Hello world");
   return text;
}

as for as i know , there is only one error..... you have
declared text as array of pointers and not as character data
array..... so this text can only accept addresses.... :)  

char *text[20] means you are going to store 20 addresses in
this array..... When you store addresses using arrays , the
that is called array of pointers....

if u declare :   char text[20] , this will work correctly..



thank u

void main()
{
int a = 5;
int b = 7;
int c = 2;
int res;

res = (int)(a/b)?a:b;
res = (int)(res/c)?res:c;

printf("big num = %d",res);
}

#include<stdio.h>
#include<conio.h>
void main()
int a,b,c;
clrscr();
printf("enter any three no.s");
scanf("%d%d%d",&a,&b&c);
if(a>b&&a>c);
{
printf("a is biggest");
}
else if(b>a&&b>c)
{
printf("b is biggest");
}
else
printf("c is biggest");
getch();
}