(i++ > j++) gives 0 because 0 > 0 is false so it return 0.
before returning 0 i is 1 ,but it is overwrite by 0.
 In the Conditional operator false means ,it executes i++;
so i is 1.

1.we know that i=j=0 initially

2.then it will checks the non-incremented 'i' value(i.e 0) 
with incremented 'j' value(i.e 1). So obviously condition 
is falls.

3.now false statement has to be executed i.e (i--),before 
executing this 'i' value is (i.e incremented value)'1' 
after executing false condition(i.e i--)the value of 'i' 
becomes  '0'.

4.So the value of 'i' is '0'.

total=0;
k=1;
do
{
total=total+k*k*k;
k++;
}while(k<=n)

//1st method..
there is no use of j.as explained below
int j,n=psitive value;
do
{
cout<<"*";
n--;
}while(n!=0);
//2nd we can use j..
int j=0;
do
{
cout<<"*";
j++;
}while(j!=n);

Mr.Subbarao

3   3    1

its .....1 2 2

2 2 1

113

1 2 3

Answer is 5..........

declaring int i inside for loop is not available in
traditional 'c'

we can not declare loop condition variable in c..we can do
in c++.

//program for selection sort
#include<stdio.h>
#include<conio.h>
#define MX 100
void selection(int [], int);
void selection(int a[],int n)
{
	int minindx,t;
	int i,j;
	for(i=0;i<n-1;i++)
	{
		minindx=i;
		for(j=i+1;i<n;j++)
		{
			if(a[j]<a[minindx])
			minindx=j;
		}
		if(minindx!=i)
		{
		t=a[i];
		a[i]=a[minindx];
		a[minindx]=t;
		}
	}
}
void main()
{
	int a[MX],i,n;
	clrscr();
	printf("enter total num of elements:");
	scanf("%d",&n);
	for(i=0;i<n;i++)
	{
	scanf("%d",&a[i]);
	}
	selection(a,n);
	printf("sorted arrau:\n");
	for(i=0;i<n;i++)
	{
		printf("%d \t",a[i]);
	}
	getch();
}

#include<stdio.h>
#include<conio.h>
void main()
{
int n,i=1,sum=0;
clrscr();
printf("enter the value for n:");
scanf("%d",&n);
while(i<=n)
{
sum=sum+i;
i=i+2;
}
printf("the series is =%d");
getch()
}

the series seems to be infinite . so you need to restrict 
it to some ceiling.

In the answer Printf function is worng here the value for %
d is not mentioned it would like

printf("the series is =%d", sum);

#include"stdio.h"
#include"conio.h"
void main()
{
int s=0;
for(int i=1;i<100;i++)
{
if(i%2==0)
continue;
s=s+i;
}
printf("The answer is...%d",s);
getch();
}

if we want to show result as a=3,a=2..then it ll be written 
as
printf("a=3,a=2");

the printf function canbe redefined by your program using 
typedef and try this.

this is the user writtern function...... this is function 
definition statement..... it wont recoganize this statement 
because no memory will be allocated for this a=3 or 2... 
since we didnt declare it first of all/.. this may be the 
error