They took their percentages from 40 and not from 39, so they
got more than their share. 

The oldest son got 1/2 of 40 = 20 which is 0.5 more 

The second son got 1/4 of 40 = 10 which is 0.25 more 

The third son got 1/8 of 40 = 5 which is 0.125 more 

The youngest son got 1/10 of 40 = 4 which is 0.1 more 

And the stranger got 1/40 of 40 = 1 which is 0.025 more (As
he is not supposed to get anything) 

All these fractions add to = 0.5 + 0.25 + 0.125 + 0.1 +
0.025 = 1 which stranger took away.

It is obvious that between 5 O'clock and 6 O'clock the hands
will not be exactly opposite to each other. It is also
obvious that the hands will be opposite to each other just
before 5 O'clock. Now to find exact time: 

The hour hand moves 1 degree for every 12 degrees that the
minute hand moves. Let the hour hand be X degree away from 5
O'clock. Therefore the minute hand is 12X degree away from
12 O'clock. 

Therefore solving for X 

Angle between minute hand and 12 O'clock + Angle between 12
O'clock and 4 O'clock + Angle between 4 O'clock and hour
hand = 180 

12X + 120 + (30-X) = 180 

11X = 30 

Hence X = 30/11 degrees 

(hour hand is X degree away from 5 O'clock) 

Now each degree the hour hand moves is 2 minutes. 

Therefore minutes are 

= 2 * 30/11 

= 60/11 

= 5.45 (means 5 minutes 27.16 seconds) 

Therefore the exact time at which the hands are opposite to
each other is 

= 4 hrs. 54 min. 32.74 seconds

Amar and Anthony both have lassi whereas Akbar never does. 

Fact (2) can be alternatively stated that "either Amar or
Akbar or Anthony must have lassi". 

From Fact (3), it can be infered that either Amar or Akbar
must have lassi. 

Now, from Fact (1), it is apparent that Anthony too must
have lassi. But according to Fact (4), Akbar cannot have
lassi when Anthony does.

The numebr is 420. 

If statement 6 is false, it creates a paradox. Hence,
Statement 6 must be true. 

Consider Statement 2: 

?	If it is true, it must be the first true statement.
Otherwise, it creates a paradox. 

?	If it is false, it must be the second false statement.
Otherwise, it creates a paradox.

In both the cases, Statement 1 is false. 

As Statement 1 is false, Statement 9 and Statement 10 both
are false i.e. there are three consecutive true statements. 

1	2	3	4	5	6	7	8	9	10

False	-	-	-	-	True	-	-	False	False

Let\'s assume that Statement 3 is false i.e. there are no
three consecutive false statements. It means that Statement
2 and Statement 8 must be true, else there will be three
consecutive false statements. 

1	2	3	4	5	6	7	8	9	10

False	True	False	-	-	True	-	True	False	False

Also, atleast two of Statements 4, 5 and 7 must be true as
there are three consecutive true statements. 

According to Statement 8, the number that is to be found is
the percentage of true statements. Hence, number is either
50 or 60. Now if Statement 7 is true, then the number of
each true statement divides the number, that is to be found.
But 7 and 8 do not divide either 50 or 60. Hence, Statement
7 is false which means that Statement 4 and 5 are true. But
Statement 5 contradicts the Statement 8. Hence, our
assumption that Statement 3 is false is wrong and Statement
3 is true i.e. there are 3 consecutive false statements
which means that Statement 8 is false as there is no other
possibilities of 3 consecutive false statements. 

Also, Statement 7 is true as Statement 6 is not the last
true statement. 

1	2	3	4	5	6	7	8	9	10

False	-	True	-	-	True	True	False	False	False

According to Statement 7, the number of each true statement
divides the number, that is to be found. And according to
Statement 5, the sum of the numbers of the true statements
is the number, that is to be found. For all possible
combinations Statement 5 is false. 

There 3 consecutive true statements. Hence, Statement 2 and
Statement 4 are true. 

1	2	3	4	5	6	7	8	9	10

False	True	True	True	False	True	True	False	False	False

Now, the conditions for the number to be found are: 

1.	The numebr is divisible by 5 (Statement 4) 

2.	The numebr is divisible by 2, 3, 4, 6, 7 (Statement 7) 

3.	The number of divisors of the number, that is to be
found, (apart from 1 and itself) is not greater than the sum
of the numbers of the true statements. (Statement 9)

The minimum possible number is 420. 

The divisors of 420, apart from 1 and itself are 2, 3, 4, 5,
6, 7, 10, 12, 14, 15, 20, 21, 28, 30, 35, 42, 60, 70, 84,
105, 140, 210. There are total of 22 divisors. Also, the sum
of the numbers of the true statements is 22 (2+3+4+6+7=22),
which satisfies the third condition.

A simple one. Use the given facts and put down all the
players in order. The order is as follow with Harbhajan, the
highest scorer and Laxman, the lowest scorer. 

1.	Harbhajan 

2.	Ganguly 

3.	Dravid 

4.	Badani, Agarkar 

5.	Sachin 

6.	Laxman 

Also, as the lowest score was 10 runs. Laxman must have
scored 10, Sachin 20, Badani & Agarkar 30 and so on. 

1.	Harbhajan - 60 runs 

2.	Ganguly - 50 runs 

3.	Dravid - 40 runs 

4.	Badani, Agarkar - 30 runs each 

5.	Sachin - 20 runs 

6.	Laxman - 10 runs

47 seconds. 

To get 48 pieces, the boy have to put only 47 cuts. i.e. he
can cut 46 pieces in 46 seconds. After getting 46 pieces, he
will have a 2 inches long piece. He can cut it into two with
just a one cut in 1 second. Hence, total of 47 seconds.

Cruz is Tanya's date. 

As no two of them have the same number of preferred traits -
from (1), exactly one of them has none of the preferred
traits and exactly one of them has all the preferred traits. 

From (4) and (5), there are only two possibilities: 

* Adam & Cruz both are tall and Bond & Dumbo both are fair. 

* Adam & Cruz both are short and Bond & Dumbo both are dark. 

But from (2), second possibility is impossible. So the first
one is the correct possibility i.e. Adam & Cruz both are
tall and Bond & Dumbo both are fair. 

Then from (3), Bond is short and handsome. 

Also, from (1) and (2), Adam is tall and fair. Also, Dumbo
is the person without any preferred traits. Cruz is Dark.
Adam and Cruz are handsome. Thus, following are the
individual preferred traits: 

Cruz - Tall, Dark and Handsome 

Adam - Tall and Handsome 

Bond - Handsome 

Dumbo - None :-( 

Hence, Cruz is Tanya's date.

13 not 12 

He makes 9 originals from the 27 butts he found, and after
he smokes them he has 9 butts left for another 3 cigars. And
then he has 3 butts for another cigar. 

So 9+3+1=13

^^^^^^^
13

16 men, 12 women and 72 children were working with the
constructor. 

Let's assume that there were X men, Y women and Z children
working with the constructor. Hence, 

X + Y + Z = 100 

5X + 4Y + Z = 200 

Eliminating X and Y in turn from these equations, we get 

X = 3Z - 200 

Y = 300 - 4Z 

As if woman works, her husband also works and atleast half
the men working came with their wives; the value of Y lies
between X and X/2. Substituting these limiting values in
equations, we get 

if Y = X, 

300 - 4Z = 3Z - 200 

7Z = 500 

Z = 500/7 i.e. 71.428 

if Y = X/2, 

300 - 4Z = (3Z - 200)/2 

600 - 8Z = 3Z - 200 

11Z = 800 

Z = 800/11 i.e. 72.727 

But Z must be an integer, hence Z=72. Also, X=16 and Y=12 

There were 16 men, 12 women and 72 children working with the
constructor.

answer would be
2omen,with their wifes thats 20 
20*5=100
20*4=80
childrn given 1 rupees so
20chidren

The sequence of letters from the lowest value to the highest
value is TUSQRPV. 

From (3), Q is the middle term. 

___ ___ ___ _Q_ ___ ___ ___ 

From (4), there must be exactly 2 numbers between P and S
which gives two possible positions. 

[1] ___ _S_ ___ _Q_ _P_ ___ ___ 

[2] ___ ___ _S_ _Q_ ___ _P_ ___ 

From (1), the number of letters between U and Q must be same
as the number of letters between S and R. Also, the number
of letters between them can be 1, 2 or 3. 

Using trial and error, it can be found that there must be 2
letters between them. Also, it is possible only in option
[2] above. 

[2] ___ _U_ _S_ _Q_ _R_ _P_ ___ 

From (2) V must be the highest and the remaining T must be
the lowest number. 

_T_ _U_ _S_ _Q_ _R_ _P_ _V_ 

Thus, the sequence of letters from the lowest value to the
highest value is TUSQRPV.

1, 2, 4, 8, 16, 32, 64, 128, 256, 489 

Let's start from scratch. 

?	The apple vandor can ask for only 1 apple, so one box must
contain 1 apple. 

?	He can ask for 2 apples, so one box must contain 2 apples. 

He can ask for 3 apples, in that case box one and box two
will add up to 3. 

?	He can ask for 4 apples, so one box i.e. third box must
contain 4 apples. 

?	Now using box number one, two and three containing 1, 2
and 4 apples respectively, his son can give upto 7 apples.
Hence, forth box must contain 8 apples. 

?	Similarly, using first four boxes containing 1, 2, 4 and 8
apples, his son can give upto 15 apples. Hence fifth box
must contain 16 apples. 

?	You must have noticed one thing till now that each box
till now contains power of 2 apples. Hence the answer is 1,
2, 4, 8, 16, 32, 64, 128, 256, 489. This is true for any
number of apples, here in our case only upto 1000.

7.5 degrees 

At 3:15 minute hand will be perfactly horizontal pointing
towards 3. Whereas hour hand will be towards 4. Also, hour
hand must have covered 1/4 of angle between 3 and 4. 

The angle between two adjacent digits is 360/12 = 30 degrees. 

Hence 1/4 of it is 7.5 degrees.

-15 degree

A very TOUGH puzzle !!! 

POS	FIRST NAME 	LAST NAME 	BUSINESS

1	Sachi	Loti	? Fill Out a Change-of-Address Form

? Add Postage to Meter

2	Gianni	Lau	? Pick Up a Registered Letter

? Send an Item Parcel Post

3	Carlos	Pimentelli	? Overnight Package

? Send Airmail to Tibet

4	Donna	Toriseza	? Buy Stamps

? Send an Insured Package

5	Mary	Knutson	? Buy a Money Order

? Send Books fourth Class

6	Anthony	Rendler	? Complain About a Mail Carrier

? Pick Up a Package

Sachin, Dravid and Ganguly scored 75, 87 and 78 respectively. 

Sachin's score must be less than 86, otherwise Dravid's
score would be more than 99. Also, he must have scored
atleast 42 - incase Dravid and Ganguly scored 99 each. 

Also, as none of them scored more than 99 and the total runs
scored by them is 240; their individual scores must be
around 80. 

Now, use trial-n-error method to solve the teaser.

Blue box contains the maximum amount Rs. 40000 

As it is given that only one of the given 3 statements is
true; assume in turn, each statement to be true & the other
2 false and check whether the corresponding box contains the
maximum amount. 

Let's assume that the statement on the Blue box is true.
Thus, the given 3 statements can be interpreted as 

* Atmost one, a red box or a blue box contains Rs. 10000. 

* Atmost one, a green box or a red box contains Rs. 25000. 

* Both, a blue box and a green box contain Rs. 15000 each. 

Going through all possible combinations, we can conclude that 

Red Box : Rs. 10000 + Rs. 25000 = Rs. 35000 

Green Box : Rs. 10000 + Rs. 15000 = Rs. 25000 

Blue Box : Rs. 15000 + Rs. 25000 = Rs. 40000 

You can test out for other two statements i.e. assuming Red
box statement true and then Green box statement true. In
both the cases, other statements will contradict the true
statement.