274

211

1111

121

224

1008

238

rediffmail.com

Semaphores

no

1236547890

1234567890

1356792480

1234567890

Unless Ive read the question wrong, none of these answers
are correct. Ans 1 & 2 dont divide with 7 digits. Ans 3
doesnt divide with 2 digits.

So far the only thing we can deduce is that the 5th digit
must be 5 so that the number is divisible by 5 and the 10th
digit must be 0 so that it is divisible by 10.

123654...0

3816547290

i wii help for the old lady because i may have another 
chance to pay back my friend

hi mohan it is not a Emotional question it’s was asked in 
interview time for checked the presence of mind of the 
candidate “The ans is “”The candidate who was hired (out of 
200 applicants) had no trouble coming up with his answer. 
Guess what was his answer?


He simply answered: 


"I would give the car keys to my Old friend and let him 
take the lady to the hospital. 
I would stay behind and wait for the bus with the partner 
of my dreams."

i would like 2 help the old lady exactly.bcoz she s about to
die n infront of her nothing is more for me.

THE  ANS.. GIVEN BY MADHU IS CORRECT ....

6.
each of them shared 4 bullets and the remaining bullets are
2 of each which is equal to initial count.

initially there were 18 bullets.
each person had 6 bullets.
after firing 4 bullets remaining were 2 each and the sum is 
6,which was initially each one's share

initially they had 18 bullets which was equally partitioned 
among 3 of them the share was given to each of the three 
and each of thenm used 4 bullets from their share so the 
remainin is 2 in each share and the sum wud bring 6(2+2+2)
and this was the individual share given to each so again 
the sum brings 18(6+6+6).so 18 is the answer

let the no of bullets each hav be x
then after firing 4 bullets
each hav x-4 bullets 
so,x-4+x-4+x-4=x
    3x-12=x;
    x=6
so the number of bullets each hav is 6.
3 persons mens 3*6=18
the total number of bullets is 18(ans)

first batsman takes a single,while attempting to take the 
second run the fielder throws the ball to avoid the second 
run but the ball goes and hits the helmet which is at the 
keeper place,so 1+(5 runs for the helmet)=94+1+5=60 and the 
other batsman hits a 6 of the second ball.

first batsman hit a 6 for fourth ball afterthis he will run 
for one run but he is run out thats why another batsman go 
on strike and hit a 6  thats it

the man in the crease hits a six for first ball n completes
his centuary.when he s about to have a single for next ball
he will be run out.here matcross will be done so that other
bats man will be in the crease. and for the last ball he
will hit a six and completes his centuary.thats it
..........so simple na.....

Nadeem Shaikh : All the above answer are wrong
because when the ball hots the helmet the runs 
are given to the team not to batsman.
and other says for runout but the question 
is both batsmen should be notut.
Correct answer is that a batman hit a
boundary and then runs three for the next ball 
and runs one run short and then next batsman
hits a six on the last ball.

Dear Nadeem,

            If the first batsman hit  boundary and take 
three run the team wins...No chance for other to face a 
ball. Are you sure runs from helemet goes to team only!If 
so we have to wait for new answer!!!!!!!!

Yes its possible in any of the combination [ 6 + 0 + 1  / 3 
+ 2 + 2 ....etc ]

Reason : Since it hasn't mentioned that each batsman is on 
94 runs - I take it has its aggregate score of two batsman. 

So both batsman together could have got unbeaten 100.

one batsman hits for a six.. over end... the next one hits 
for another six..... it has not been mentioned whether all 
3 balls have to be used..

Dear Midhun, i think Nadeem is right.....he said the 3rd run
was a runshort so it wont be counted....

Batsman A is on strike, he makes a single but the fielding
team makes a mess of returning the ball and it goes to the
boundary as overthrows (which incidentally do go to the
batsmen), he will now have 99, then he plays single to get
to 100 and batsmen B then hits a 6.

the previous answer is correct

first person (2+1)and another one (4).

All the above answer are wrong
because when the ball hIts the helmet...SURELY... the runs 
are given to the team not to batsman.
and other says for runout but the question 
is both batsmen should be UNBEATEN.
Correct answer is that a batman hit a
boundary and then runs three for the next ball 
and runs one run short and then next batsman
hits a six on the last ball.

162

122

3+7=10,10*2=20,20+7=27,27*2=54,54+7=61,61*2=122

122

its 122

3+7=10
3+7+10=20
20+7=27
27+20+7=54
54+7=61
61+54+7=122

3+7=10
10+10=20
20+7=27
27+27=54
54+7=61
61+61=122

3
    13
        17
10
    30 
20       17
    47 
         34
27
    81 
         34
54
    115
          51
61

     166
105

122

we need to have one or more balls, so its like a position 
where we should not be with no balls.

so answer is (total number of ways we can select the balls 
in all possible ways) - (no. of ways where we don't have 
any balls selected)

So, no. of ways where we don't have any balls selected = 
10C0*9C0*7C0 = 1

total number of ways we can select the balls in all 
possible ways = 10!*9!*7!/(10*9*7)

so, answer is ((10!*9!*7!)/(10*9*7)) - 1 =

26C1 + 26C2 +........+26C26

26c1+25c2