65 .

3.5

8

The ans is 31.
Explaination: There are in total 31 breads.
1st person ate 15.5+ 0.5 bread
2nd person ate 7.5+0.5 bread
3rd person ate 3.5+0.5 bread
4th person ate 1.5+0.5 bread
5th person ate 0.5+0.5 bread

let the total no of breads be x. 

     1st man        2nd man 
x-  (x/2) - 1/2  - 1/2((x-1)/2) - 1/2 ..... so on.

ans is 31.

first ate : 15.5 + .5 = 16 remaining 15
second ate : 7.5+0.5 = 8 remaining 7.
third ate : 3.5 +0.5 = 4 remaining 3.
fourth ate : 1.5 + 0.5 = 2 remaining 1
fifth ate : 0.5 + 0.5 = 1 remaining 0

x= (x/2+1/2)+(x/4 +1/2)+(x/8+1/2)+(x/16+1/2)+(x/32+1/2)

hence 
x=2.5+(31/32)x
(1/32)x=2.5
x=2.5*32
x=80

since the product is 72, there are only 12 possibilities.
the product and sum are
1  1  72  = 74   2  2  18 = 22
1  2  36  = 39   2  3  12 = 17
1  3  12  = 16   2  4   9 = 15
1  4  18  = 23   2  6   6 = 14
1  6  12  = 19   3  3   8 = 14
1  8   9  = 18   3  4   6 = 13
since the sum of their ages gives the door number of venkat 
and venkat needs some more information, indicates that 
there should be two same sums. that is 
2  6  6 = 14
3  3  8 = 14
since the boy is the elder of three, he could be eight 
years old. so the ages are the daughters are age 3 and boy 
is aged 8.

gr888 ans thank u frnd.

9,4and 2

It can be also 6, 4 and 3

in 4 rooms the lights are made on

01101
01110
00111
11011
11000

... and rotations of this.

The problem can be written as a system of 25 equations in 25
unknown over the field Z mod two, and then solved using
linear algebra (hopefully with the aid of a computer).

just switch on the 5 lights in the rooms to the right

U have to on 4 light only.

The room of which light need to on is indicated by 0, 

11111
10101
11111
10101
11111

f6b2b
gfabc
7a1a3
geadc
e5d4d

1,2,3,4,5,6,7 indicate switch-rooms in order of switching 
on their switches.
a corresponds to adjuscent rooms which lit due to step 1
b corresponds to adjuscent rooms which lit due to step 2
....
g corresponds to adjuscent rooms which lit due to step 7

X1X1X      Superman,if u on 4 lights,then switches of the
10101      room denoted by X will not be turned on.
X1X1X
10101
X1X1X
.........................................................
U have to on 7 lights 

The room of which light need to on is indicated by 0,

11011
01110
11011
01110
11011

77,777

343,707

48,84
I believe the above 2 answers are not appropriate because, 
the question says "if digits of X are reversed then we 
obtain NEW number say Y". i.e., The digits arent Palindrome.

consider any 3 digit number first...
100a+10b+c
reverse it-
100c+10b+a
if these two numbers are divisible by 7 even their
difference must be
so 
99(a-c) is div by 7
-> a-c=7n
c can't be 0
so possible combinations-
8,1(you can also consider n=0 ->a=c)
and 9,2 ->numbers- 952,259,861,168(palindromes-707,77,868,777)

palindromes won't work.
since when the digits of X are reversed,it should be a new 
number Y. 77,707,343 and 777 ,all on reversing is giving 
the same number.

The correct answer is D i.e. 33.3
if x = amt sold at 5% profit, y = amt sold at 20% profit
x+y=100
5x + 20y = 1500
solving the above equations we get
x=33.3

Initial	
8 lt Jar	8lt milk
5 lt Jat	Empty
3 lt Jar	Empty

1st step	
8 lt Jar	3 lt milk
5 lt Jat	5 lt milk
3 lt Jar	empty

2nd step	
8 lt Jar	3 lt milk
5 lt Jat	2 lt milk
3 lt Jar	3 lt milk

3rd step	
8 lt Jar	6 lt milk
5 lt Jat	2 lt milk
3 lt Jar	empty

4th step	
8 lt Jar	6 lt milk
5 lt Jat	empty
3 lt Jar	2 lt milk

5th step	
8 lt Jar	1 lt milk
5 lt Jat	5 lt milk
3 lt Jar	2 lt milk

6th step	
8 lt Jar	1 lt milk
5 lt Jat	4 lt milk
3 lt Jar	3 lt milk

7th step	
8 lt Jar	4 lt milk
5 lt Jat	4 lt milk
3 lt Jar	empty

8lit   5lit   3lit

 8      0      0
 3      5      0
 3      2      3
 6      2      0
 6      0      2
 1      5      2
 1      4      3
 4      4      0.   hence finally we have 4 lit in 8 lit 
jar,and 4 lit in 5 lit jar.hence solved.

8 ltr   5 ltr    3 ltr 

8        0        0 
5        0        3
5        3        0
2        3        3
1        3        4 ( POUR FROM 8 TO 3 TILL 3 GETS FULL )
0        4        4 

( MINIMUM NO OF STEPS = 5)

origial 8     0        0
        3     5        0
        3     2        3
        6     2        0
        6     0        2
        1     5        2
        1     4        3
        4     4        0

8lts   5lts  3lts
8      0      0
5      0      3
5      3      0
2      3      3
2      5      1
7      0      1
7      1      0
4      1      3
4      4      0

8lts   5lts  3lts
8      0      0
3      5      0
3      2      3
6      0      2
1      5      2
1      4      3
4      4      0

8       0        0
0       5        3
3       5        0
3       2        3
6       2        0
6       0        2
1       5        2
1       4        3
4       4        0

chander=c sunder=s maninder=m

1. if m sees two white caps infront of him on c and s he
would have answered black. when he says he doesnot know that
sures one thing that c and s are wearing combination of
white and black or both black.
2. if s sees a white cap on c he would have readily shouted
black as if his head had white cap then m would have
answered the question, since m didnt. now if he sees a black
cap on c head he again does not know whether his head has
black or white. 
3.since s answered doesn't know, c catches the point that he
is wearing a BLACK CAP.

person in back has three scenarios where he would be
uncertain; if the front combo is black and black or black
and white. knowing that, the person in front has one
scenario to be uncertain in in those two scenarios; if the
guy in front of him is wearing a white hat he knows that
his(second) hat will be black in order to make the third guy
uncertain but if the front most guy is wearing a black hat
then the second guy can be wearing either white or black.
knowing this, the frontmost guy will know he has a black hat.

1. Maninder  –  Can answer when others are wearing white 
caps. But he gets confused as Sunder & Chander are wearing 
either combination of Black & White or both Black caps. 

2. Sunder -  Since Manindar doesn’t know his cap color, 
Sunder also concluded that he and Chander are wearing 
either combination of Black & White or both Black caps.
If Chander wares white cap then Sunder may answered as 
Black for himself. But  Chander is wearing Black so there 
are chances of wearing himself as Black or White caps. So 
he is not in the position to conclude.

3. Based on the above 2 guys conclusion only option for 
Chander to conclude for himself is wearing Black and 
answered.

he is wearing black cat

from the above we come to know that Brain is lawyer and 
Derk is a Vet, IT say Alan Earned more than Barin and the 
Doctor earned more than Derk. Once catching point is that 
Brian and Derk did not start with 10,000 pound salary.

Name     Profession  Salary
Alan     MP          ?14,000
Brian    lawyer      ?12,000
Charles  doctor      ?10,000
Derek    vet         ? 8,000

brain is layer   ......   salary is   8000
derek is vet     ......   salary is  10000
alan is doctor   ......   salary is  12000
carles is mp     ......   salary is  14000

name      painting   position
mary      monkey        1
jonney    constable     2
priya     flower        3
sachin    temple        4

Name      1stgame     2ndgame
Kiev        1            2
Richard     2            1
John        3            4
Stuart      4            3

25.6 ish.

Depends wether it means 1.5% as a percentage of the paper 
rate or as a percentage of the 6.5% inflation on the paper 
rate. In the case of the latter, you should :

25 * 0.065 * 1.015  + 25 = x ( cost after one year ).

x * 0.065 * 1.015 + x = 29.4

In the case of the former the total increase rate is 1.5% + 
6.5% = 8%

so 

25 * 1.08 * 1.08 = 29.16

Ans. 29.16

Total inflation = 6.5+1.5 for 1 year.

25 ( 1 + 8/100)^2 = 29.16

The queen gave two rings to two daughter's and she kept the 
third ring in her jewel box and she presented the ring to 
her third daughter along with that jewel box.

she keeps the ring she wears in that box.

CASE 1:  First we should take six balls divided equally and 
then it is placed on the two pans.three on one and three on 
other..
if the two pans are balanced then the defective ball is not 
in the six..then we should the two and keep them one ball 
on each.
CASE2:   Again We should take any of the six balls and 
divided equally and then it is placed on the two pans.. if 
any of the pan weighs less than the other.. We should take 
the three balls seperately..Now from that three we should 
take any two and placed one on each.. fi both the pan 
balances the ball which is left over is the defective.. if 
one ball weighes less than the other,while keeping one on 
each,then it is the defective one....

divide the balls into three groups. Let group A contains 3 
balls group B contains 3 balls and group C contains 2 balls.
FIRST TIME: BALANCE the groups A and B. 
case 1:
If they are equal then the defective ball is in group C.
case 2: if they are not equal then take the group of 3 
balls which has less weight.
SECOND TIME:
IF the defective ball is in group C, we can easily find the 
ball which is less.
if the defective ball is in group of 3 which has less 
weight, take 2 balls out of this group and find the weight.
if they are equal, then the left out is defective. if not 
we can find easily the ball which weigh less.
so we have the following steps:
                 A (3)    B(3)    c(2)
                |_____________|     |
first time            /\            |
                unequal equal then c has defective.use
                  |            second time to find out
second time   take lessweight group

By Using  Divide and Conquer Mechanism easily we can
find the defective one.

95m/sec

speed of 1st car=>72kmph=72*5/18m/sec=20m/sec.
speed of second car=>25m/sec.
Therefore difference in their speed =5m/sec.

5 m/s

FIRSTLY CONVERT 72KMPH INTO MPS ie 72*5/18 gives 20mps
speed of 2n dis 25mps
if moving in same dir then  v1-v2 =5mps
if moving in opp dir then v1+v1 =45mps

5m/sec

In 10 minutes

in10 minuts