ALLInterview.com :: Home Page KalAajKal.com
 Advertise your Business Here     
Browse  |   Placement Papers  |   Company  |   Code Snippets  |   Certifications  |   Visa Questions
Post Question  |   Post Answer  |   My Panel  |   Search  |   Articles  |   Topics  |   ERRORS new
   Refer this Site  Refer This Site to Your Friends  Site Map  Bookmark this Site  Set it as your HomePage  Contact Us     Login  |  Sign Up                      
tip       Ask Questions on ANYTHING, that arise in your Daily Life at     FORUM9.COM
Google
 
Categories  >>  Code Snippets  >>  Programming Code  >>  C Code
 
 


 

 
 C Code interview questions  C Code Interview Questions
 C++ Code interview questions  C++ Code Interview Questions
 VC++ Code interview questions  VC++ Code Interview Questions
 Java Code interview questions  Java Code Interview Questions
 Dot Net Code interview questions  Dot Net Code Interview Questions
 Visual Basic Code interview questions  Visual Basic Code Interview Questions
 Programming Code AllOther interview questions  Programming Code AllOther Interview Questions
Question
main()

      { 

		int a=10,*j;

      	void *k; 

		j=k=&a;

        	j++;  

		k++;

        	printf("\n %u %u ",j,k);

      }
 Question Submitted By :: Susie
I also faced this Question!!     Rank Answer Posted By  
 
  Re: main() { int a=10,*j; void *k; j=k=&a; j++; k++; printf("\n %u %u ",j,k); }
Answer
# 1
Answer :  

		Compiler error: Cannot increment a void pointer

      Explanation:

Void pointers are generic pointers and they can be used only
when the type is not known and as an intermediate address
storage type. No pointer arithmetic can be done on it and
you cannot apply indirection operator (*) on void pointers.
 
Is This Answer Correct ?    2 Yes 0 No
Susie
 

 
 
 
Other C Code Interview Questions
 
  Question Asked @ Answers
 
struct point { int x; int y; }; struct point origin,*pp; main() { pp=&origin; printf("origin is(%d%d)\n",(*pp).x,(*pp).y); printf("origin is (%d%d)\n",pp->x,pp->y); }  1
Give a one-line C expression to test whether a number is a power of 2. Microsoft8
Write a routine that prints out a 2-D array in spiral order Microsoft2
print numbers till we want without using loops or condition statements like specifically(for,do while, while swiches, if etc)!  7
main() { int i=10; void pascal f(int,int,int); f(i++,i++,i++); printf(" %d",i); } void pascal f(integer :i,integer:j,integer :k) { write(i,j,k); }  1
main( ) { int a[2][3][2] = {{{2,4},{7,8},{3,4}},{{2,2},{2,3},{3,4}}}; printf(“%u %u %u %d \n”,a,*a,**a,***a); printf(“%u %u %u %d \n”,a+1,*a+1,**a+1,***a+1); }  1
#define int char main() { int i=65; printf("sizeof(i)=%d",sizeof(i)); }  1
main() { if ((1||0) && (0||1)) { printf("OK I am done."); } else { printf("OK I am gone."); } } a. OK I am done b. OK I am gone c. compile error d. none of the above HCL1
main() { char c; int i = 456; clrscr(); c = i; printf("%d", c); } a. 456 b. -456 c. random number d. none of the above HCL1
main() { int x=5; clrscr(); for(;x==0;x--) { printf("x=%d\n”", x--); } } a. 4, 3, 2, 1, 0 b. 1, 2, 3, 4, 5 c. 0, 1, 2, 3, 4 d. none of the above HCL1
main() { char *p; int *q; long *r; p=q=r=0; p++; q++; r++; printf("%p...%p...%p",p,q,r); }  1
#define square(x) x*x main() { int i; i = 64/square(4); printf("%d",i); }  1
main() { int i=10; i=!i>14; Printf ("i=%d",i); }  1
#define max 5 #define int arr1[max] main() { typedef char arr2[max]; arr1 list={0,1,2,3,4}; arr2 name="name"; printf("%d %s",list[0],name); }  1
#define FALSE -1 #define TRUE 1 #define NULL 0 main() { if(NULL) puts("NULL"); else if(FALSE) puts("TRUE"); else puts("FALSE"); }  1
main() { unsigned int i=65000; while(i++!=0); printf("%d",i); }  1
#include<conio.h> main() { int x,y=2,z,a; if(x=y%2) z=2; a=2; printf("%d %d ",z,x); }  1
main() { void swap(); int x=10,y=8; swap(&x,&y); printf("x=%d y=%d",x,y); } void swap(int *a, int *b) { *a ^= *b, *b ^= *a, *a ^= *b; }  1
main() { static int a[3][3]={1,2,3,4,5,6,7,8,9}; int i,j; static *p[]={a,a+1,a+2}; for(i=0;i<3;i++) { for(j=0;j<3;j++) printf("%d\t%d\t%d\t%d\n",*(*(p+i)+j), *(*(j+p)+i),*(*(i+p)+j),*(*(p+j)+i)); } }  1
main() { char *a = "Hello "; char *b = "World"; clrscr(); printf("%s", strcpy(a,b)); } a. “Hello” b. “Hello World” c. “HelloWorld” d. None of the above HCL1
 
For more C Code Interview Questions Click Here 
 
 
 
 
 
   
Copyright Policy  |  Terms of Service  |  Help  |  Site Map 1  |  Articles  |  Site Map  |   Site Map  |  Contact Us interview questions urls   External Links 
   
Copyright © 2007  ALLInterview.com.  All Rights Reserved.

ALLInterview.com   ::  Forum9.com   ::  KalAajKal.com