| Other C Code Interview Questions |
| |
| Question | Asked @ | Answers |
| |
| void main()
{
int const * p=5;
printf("%d",++(*p));
} | | 1 |
| main()
{
int i;
i = abc();
printf("%d",i);
}
abc()
{
_AX = 1000;
} | | 1 |
| Given a list of numbers ( fixed list) Now given any other
list, how can you efficiently find out if there is any
element in the second list that is an element of the
first list (fixed list) | Disney | 3 |
| How do you write a program which produces its own source
code as its output?
| | 7 |
| Given an array of size N in which every number is between 1
and N, determine if there are any duplicates in it. You are
allowed to destroy the array if you like. | Microsoft | 15 |
| main()
{
struct student
{
char name[30];
struct date dob;
}stud;
struct date
{
int day,month,year;
};
scanf("%s%d%d%d", stud.rollno, &student.dob.day,
&student.dob.month, &student.dob.year);
} | | 1 |
| What is "far" and "near" pointers in "c"...? | | 3 |
| #define FALSE -1
#define TRUE 1
#define NULL 0
main() {
if(NULL)
puts("NULL");
else if(FALSE)
puts("TRUE");
else
puts("FALSE");
} | | 1 |
| plz send me all data structure related programs | | 2 |
| main()
{
char *p="GOOD";
char a[ ]="GOOD";
printf("\n sizeof(p) = %d, sizeof(*p) = %d, strlen(p) = %d",
sizeof(p), sizeof(*p), strlen(p));
printf("\n sizeof(a) = %d, strlen(a) = %d",
sizeof(a), strlen(a));
} | | 1 |
| #define SQR(x) x * x
main()
{
printf("%d", 225/SQR(15));
}
a. 1
b. 225
c. 15
d. none of the above | HCL | 1 |
| main()
{
int x=5;
clrscr();
for(;x==0;x--) {
printf("x=%d\n”", x--);
}
}
a. 4, 3, 2, 1, 0
b. 1, 2, 3, 4, 5
c. 0, 1, 2, 3, 4
d. none of the above | HCL | 1 |
| main()
{
char name[10],s[12];
scanf(" \"%[^\"]\"",s);
}
How scanf will execute? | | 1 |
| #include <stdio.h>
main()
{
char * str = "hello";
char * ptr = str;
char least = 127;
while (*ptr++)
least = (*ptr<least ) ?*ptr :least;
printf("%d",least);
} | | 1 |
| void main()
{
static int i=i++, j=j++, k=k++;
printf(“i = %d j = %d k = %d”, i, j, k);
} | | 1 |
| main()
{
int a=2,*f1,*f2;
f1=f2=&a;
*f2+=*f2+=a+=2.5;
printf("\n%d %d %d",a,*f1,*f2);
} | | 1 |
| main()
{
int i=_l_abc(10);
printf("%d\n",--i);
}
int _l_abc(int i)
{
return(i++);
} | | 1 |
| #define DIM( array, type) sizeof(array)/sizeof(type)
main()
{
int arr[10];
printf(“The dimension of the array is %d”, DIM(arr,
int));
} | | 1 |
| void main()
{
int i=5;
printf("%d",i++ + ++i);
} | | 1 |
| main()
{
int i=5;
printf("%d%d%d%d%d%d",i++,i--,++i,--i,i);
} | | 1 |
| |
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