#define assert(cond) if(!(cond)) \ (fprintf(stderr, "assert

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Question

#define assert(cond) if(!(cond)) \

        (fprintf(stderr, "assertion failed: %s, file %s,
line %d \n",#cond,\

       __FILE__,__LINE__), abort())

      void main()

      {

      int i = 10;

      if(i==0)	

          assert(i < 100); 

      else

          printf("This statement becomes else for if in
assert macro");

      }

Question Submitted By :: Susie

I also faced this Question!!

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Answer Posted By

Re: #define assert(cond) if(!(cond)) \ (fprintf(stderr, "assertion failed: %s, file %s, line %d \n",#cond,\ __FILE__,__LINE__), abort()) void main() { int i = 10; if(i==0) assert(i < 100); else printf("This statement becomes else for if in assert macro"); }

Answer
# 1

Answer : 

      No output

      Explanation:

The else part in which the printf is there becomes the else
for if in the assert macro. Hence nothing is printed. 

      The solution is to use conditional operator instead of
if statement,

#define assert(cond) ((cond)?(0): (fprintf (stderr,
"assertion failed: \ %s, file %s, line %d \n",#cond,
__FILE__,__LINE__), abort()))

      Note:

However this problem of “matching with nearest else” cannot
be solved by the usual method of placing the if statement
inside a block like this,

      #define assert(cond) { \

      if(!(cond)) \

        (fprintf(stderr, "assertion failed: %s, file %s,
line %d \n",#cond,\

       __FILE__,__LINE__), abort()) \

      }

Is This Answer Correct ?

0 Yes

0 No

Susie

Question	Asked @	Answers
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