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Question
int swap(int *a,int *b)

      {

       *a=*a+*b;*b=*a-*b;*a=*a-*b;

      }

      main()

      {

		int x=10,y=20;

      	swap(&x,&y);

		printf("x= %d y = %d\n",x,y);

      }
 Question Submitted By :: Susie
I also faced this Question!!     Rank Answer Posted By  
 
  Re: int swap(int *a,int *b) { *a=*a+*b;*b=*a-*b;*a=*a-*b; } main() { int x=10,y=20; swap(&x,&y); printf("x= %d y = %d\n",x,y); }
Answer
# 1
Answer : 

	x = 20 y = 10

Explanation

This is one way of swapping two values. Simple checking will
help understand this.
 
Is This Answer Correct ?    0 Yes 0 No
Susie
 

 
 
 
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