What is the output for the program given below typedef enum

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Question

What is the output for the program given below 

           typedef enum errorType{warning, error,
exception,}error;

           main()

          {

              error g1;

              g1=1; 

              printf("%d",g1);

           }

Question Submitted By :: Susie

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Re: What is the output for the program given below typedef enum errorType{warning, error, exception,}error; main() { error g1; g1=1; printf("%d",g1); }

Answer
# 1

Answer : 

		Compiler error: Multiple declaration for error

      Explanation

      The name error is used in the two meanings. One means
that it is a enumerator constant with value 1. The another
use is that it is a type name (due to typedef) for enum
errorType. Given a situation the compiler cannot distinguish
the meaning of error to know in what sense the error is used: 

      	error g1;

      g1=error; 

      	// which error it refers in each case?

      When the compiler can distinguish between usages then
it will not issue error (in pure technical terms, names can
only be overloaded in different namespaces).

      Note: the extra comma in the declaration,

      enum errorType{warning, error, exception,}

is not an error. An extra comma is valid and is provided
just for programmer’s convenience.

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Susie

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