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Question
What is the output of the program given below

      main()

          {

             signed char i=0;

             for(;i>=0;i++) ;

             printf("%d\n",i);

          }
 Question Submitted By :: Susie
I also faced this Question!!     Rank Answer Posted By  
 
  Re: What is the output of the program given below main() { signed char i=0; for(;i>=0;i++) ; printf("%d\n",i); }
Answer
# 1
Answer : 

		-128

      Explanation

Notice the semicolon at the end of the for loop. THe initial
value of the i is set to 0. The inner loop executes to
increment the value from 0 to 127 (the positive range of
char) and then it rotates to the negative value of -128. The
condition in the for loop fails and so comes out of the for
loop. It prints the current value of i that is -128.
 
Is This Answer Correct ?    0 Yes 0 No
Susie
 

 
 
 
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