Question
void pascal f(int i,int j,int k)
{
printf(%d %d %d,i, j, k);
}
void cdecl f(int i,int j,int k)
{
printf(%d %d %d,i, j, k);
}
main()
{
int i=10;
f(i++,i++,i++);
printf(" %d\n",i);
i=10;
f(i++,i++,i++);
printf(" %d",i);
}
Question Submitted By :: Susie
I also faced this Question!!
Rank
Answer Posted By
Re: void pascal f(int i,int j,int k)
{
printf(%d %d %d,i, j, k);
}
void cdecl f(int i,int j,int k)
{
printf(%d %d %d,i, j, k);
}
main()
{
int i=10;
f(i++,i++,i++);
printf(" %d\n",i);
i=10;
f(i++,i++,i++);
printf(" %d",i);
}
Answer 1 Answer :
10 11 12 13
12 11 10 13
Explanation:
Pascal argument passing mechanism forces the arguments
to be called from left to right. cdecl is the normal C
argument passing mechanism where the arguments are passed
from right to left.
Susie
Other C Code Interview Questions Question Asked @ Answers Given an array of characters which form a sentence of
words, give an efficient algorithm to reverse the order of
the words (not characters) in it.
Microsoft 7 void pascal f(int i,int j,int k)
{
printf(%d %d %d,i, j, k);
}
void cdecl f(int i,int j,int k)
{
printf(%d %d %d,i, j, k);
}
main()
{
int i=10;
f(i++,i++,i++);
printf(" %d\n",i);
i=10;
f(i++,i++,i++);
printf(" %d",i);
} 1 How to read a directory in a C program?
4 int aaa() {printf(Hi);}
int bbb(){printf(hello);}
iny ccc(){printf(bye);}
main()
{
int ( * ptr[3]) ();
ptr[0] = aaa;
ptr[1] = bbb;
ptr[2] =ccc;
ptr[2]();
} 1 write the function. if all the character in string B appear in
string A, return true, otherwise return false. Google 10 main(){
int a= 0;int b = 20;char x =1;char y =10;
if(a,b,x,y)
printf("hello");
} 1 Write a C function to search a number in the given list of
numbers. donot use printf and scanf Honeywell 4 main()
{
char c=' ',x,convert(z);
getc(c);
if((c>='a') && (c<='z'))
x=convert(c);
printf("%c",x);
}
convert(z)
{
return z-32;
} 1 main(int argc, char *argv[])
{
(main && argc) ? main(argc-1, NULL) : return 0;
}
a. Runtime error.
b. Compile error. Illegal syntax
c. Gets into Infinite loop
d. None of the above HCL 1 how to return a multiple value from a function? Wipro 2 void main()
{
static int i=5;
if(--i){
main();
printf("%d ",i);
}
} 1 union u
{
struct st
{
int i : 4;
int j : 4;
int k : 4;
int l;
}st;
int i;
}u;
main()
{
u.i = 100;
printf("%d, %d, %d",u.i, u.st.i, u.st.l);
}
a. 4, 4, 0
b. 0, 0, 0
c. 100, 4, 0
d. 40, 4, 0 HCL 1 main()
{
int i =0;j=0;
if(i && j++)
printf("%d..%d",i++,j);
printf("%d..%d,i,j);
} 1 #include<stdio.h>
void fun(int);
int main()
{
int a;
a=3;
fun(a);
printf("\n");
return 0;
}
void fun(int i)
{
if(n>0)
{
fun(--n);
printf("%d",n);
fun(--n);
}
} the answer is 0 1 2 0..someone explain how the code is
executed..? Wipro 1 main()
{
char not;
not=!2;
printf("%d",not);
} 1 main()
{
static char
names[5][20]={"pascal","ada","cobol","fortran","perl"};
int i;
char *t;
t=names[3];
names[3]=names[4];
names[4]=t;
for (i=0;i<=4;i++)
printf("%s",names[i]);
} 1 #define max 5
#define int arr1[max]
main()
{
typedef char arr2[max];
arr1 list={0,1,2,3,4};
arr2 name="name";
printf("%d %s",list[0],name);
} 1 main()
{
int i = 258;
int *iPtr = &i;
printf("%d %d", *((char*)iPtr), *((char*)iPtr+1) );
} 1 void main()
{
static int i=i++, j=j++, k=k++;
printf(i = %d j = %d k = %d, i, j, k);
} 1 void main()
{
int *mptr, *cptr;
mptr = (int*)malloc(sizeof(int));
printf(%d,*mptr);
int *cptr = (int*)calloc(sizeof(int),1);
printf(%d,*cptr);
} 1 For more C Code Interview Questions Click Here
To Refer this Site to Your Friends 
Site Map
