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Question
main()

	{

	char *str1="abcd";

	char str2[]="abcd";

	printf("%d %d %d",sizeof(str1),sizeof(str2),sizeof("abcd"));

	}
 Question Submitted By :: Susie
I also faced this Question!!     Rank Answer Posted By  
 
  Re: main() { char *str1="abcd"; char str2[]="abcd"; printf("%d %d %d",sizeof(str1),sizeof(str2),sizeof("abcd")); }
Answer
# 1
Answer : 

      2 5 5

      Explanation:

In first sizeof, str1 is a character pointer so it gives you
the size of the pointer variable. In second sizeof the name
str2 indicates the name of the array whose size is 5
(including the '\0' termination character). The third sizeof
is similar to the second one.
 
Is This Answer Correct ?    1 Yes 0 No
Susie
 

 
 
 
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