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Question
main( )

      {

       void *vp;

       char ch = ‘g’, *cp = “goofy”;

       int j = 20;

       vp = &ch;

       printf(“%c”, *(char *)vp);

       vp = &j;

       printf(“%d”,*(int *)vp);

       vp = cp;

       printf(“%s”,(char *)vp + 3);

      }
 Question Submitted By :: Susie
I also faced this Question!!     Rank Answer Posted By  
 
  Re: main( ) { void *vp; char ch = ‘g’, *cp = “goofy”; int j = 20; vp = &ch; printf(“%c”, *(char *)vp); vp = &j; printf(“%d”,*(int *)vp); vp = cp; printf(“%s”,(char *)vp + 3); }
Answer
# 1
Answer : 

      	g20fy

      Explanation:

Since a void pointer is used it can be type casted to any 
other type pointer. vp = &ch  stores address of char ch and
the next statement prints the value stored in vp after type
casting it to the proper data type pointer. the output is
‘g’. Similarly  the output from second printf is ‘20’. The
third printf statement type casts it to print the string
from the 4th value hence the output is ‘fy’.
 
Is This Answer Correct ?    0 Yes 0 No
Susie
 

 
 
 
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