| Other C Code Interview Questions |
| |
| Question | Asked @ | Answers |
| |
| Program to Delete an element from a doubly linked list.
| Infosys | 4 |
| main()
{
int i=5;
printf("%d%d%d%d%d%d",i++,i--,++i,--i,i);
} | | 1 |
| Program to find the largest sum of contiguous integers in
the array. O(n) | | 7 |
| main()
{
unsigned int i=10;
while(i-->=0)
printf("%u ",i);
} | | 1 |
| #include<stdio.h>
void fun(int);
int main()
{
int a;
a=3;
fun(a);
printf("\n");
return 0;
}
void fun(int i)
{
if(n>0)
{
fun(--n);
printf("%d",n);
fun(--n);
}
} the answer is 0 1 2 0..someone explain how the code is
executed..? | Wipro | 1 |
| Find your day from your DOB? | Microsoft | 12 |
| main()
{
int i=4,j=7;
j = j || i++ && printf("YOU CAN");
printf("%d %d", i, j);
} | | 1 |
| void main()
{
printf(“sizeof (void *) = %d \n“, sizeof( void *));
printf(“sizeof (int *) = %d \n”, sizeof(int *));
printf(“sizeof (double *) = %d \n”, sizeof(double *));
printf(“sizeof(struct unknown *) = %d \n”, sizeof(struct
unknown *));
} | | 1 |
| void main()
{
int i=i++,j=j++,k=k++;
printf(“%d%d%d”,i,j,k);
} | | 1 |
| Derive expression for converting RGB color parameters to
HSV values | | 1 |
| main()
{
int i=0;
for(;i++;printf("%d",i)) ;
printf("%d",i);
} | | 1 |
| struct point
{
int x;
int y;
};
struct point origin,*pp;
main()
{
pp=&origin;
printf("origin is(%d%d)\n",(*pp).x,(*pp).y);
printf("origin is (%d%d)\n",pp->x,pp->y);
} | | 1 |
| What is the output for the program given below
typedef enum errorType{warning, error,
exception,}error;
main()
{
error g1;
g1=1;
printf("%d",g1);
} | | 1 |
| main(){
unsigned int i;
for(i=1;i>-2;i--)
printf("c aptitude");
} | | 1 |
| main()
{
int k=1;
printf("%d==1 is ""%s",k,k==1?"TRUE":"FALSE");
} | | 1 |
| String reverse with time complexity of n/2 with out using
temporary variable. | NetApp | 8 |
| how to delete an element in an array
| | 1 |
| What is "far" and "near" pointers in "c"...? | | 3 |
| main()
{
int i = 258;
int *iPtr = &i;
printf("%d %d", *((char*)iPtr), *((char*)iPtr+1) );
} | | 1 |
| union u
{
union u
{
int i;
int j;
}a[10];
int b[10];
}u;
main()
{
printf("\n%d", sizeof(u));
printf(" %d", sizeof(u.a));
// printf("%d", sizeof(u.a[4].i));
}
a. 4, 4, 4
b. 40, 4, 4
c. 1, 100, 1
d. 40 400 4 | HCL | 1 |
| |
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