#include<stdio.h> main() { char s[]={�

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Question

#include<stdio.h>

      main()

      {

        char s[]={'a','b','c','\n','c','\0'};

        char *p,*str,*str1;

        p=&s[3];

        str=p;

        str1=s;

        printf("%d",++*p + ++*str1-32);

      }

Question Submitted By :: Susie

I also faced this Question!!

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Answer Posted By

Re: #include<stdio.h> main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); }

Answer
# 1

Answer : 

      M

      Explanation:

p is pointing to character '\n'.str1 is pointing to
character 'a' ++*p meAnswer:"p is pointing to '\n' and that
is incremented by one." the ASCII value of '\n' is 10. then
it is incremented to 11. the value of ++*p is 11. ++*str1
meAnswer:"str1 is pointing to 'a' that is incremented by 1
and it becomes 'b'. ASCII value of 'b' is 98. both 11 and 98
is added and result is subtracted from 32. 

      i.e. (11+98-32)=77("M");

Is This Answer Correct ?

0 Yes

0 No

Susie

Question	Asked @	Answers
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