| Other C Code Interview Questions |
| |
| Question | Asked @ | Answers |
| |
| main()
{
float me = 1.1;
double you = 1.1;
if(me==you)
printf("I love U");
else
printf("I hate U");
} | | 1 |
| typedef struct error{int warning, error, exception;}error;
main()
{
error g1;
g1.error =1;
printf("%d",g1.error);
} | | 1 |
| main()
{
int i=400,j=300;
printf("%d..%d");
} | | 1 |
| void main()
{
int i=5;
printf("%d",i++ + ++i);
} | | 1 |
| main()
{
char a[4]="HELLO";
printf("%s",a);
} | | 1 |
| program to find magic aquare using array | HCL | 3 |
| #define DIM( array, type) sizeof(array)/sizeof(type)
main()
{
int arr[10];
printf(“The dimension of the array is %d”, DIM(arr,
int));
} | | 1 |
| Is there any difference between the two declarations,
1. int foo(int *arr[]) and
2. int foo(int *arr[2]) | | 1 |
| main(){
unsigned int i;
for(i=1;i>-2;i--)
printf("c aptitude");
} | | 1 |
| #include<stdio.h>
main()
{
FILE *ptr;
char i;
ptr=fopen("zzz.c","r");
while((i=fgetch(ptr))!=EOF)
printf("%c",i);
} | | 1 |
| int i;
main(){
int t;
for ( t=4;scanf("%d",&i)-t;printf("%d\n",i))
printf("%d--",t--);
}
// If the inputs are 0,1,2,3 find the o/p | | 1 |
| Declare an array of N pointers to functions returning
pointers to functions returning pointers to characters? | | 1 |
| main()
{
printf("\nab");
printf("\bsi");
printf("\rha");
} | | 1 |
| #include<stdio.h>
void fun(int);
int main()
{
int a;
a=3;
fun(a);
printf("\n");
return 0;
}
void fun(int i)
{
if(n>0)
{
fun(--n);
printf("%d",n);
fun(--n);
}
} the answer is 0 1 2 0..someone explain how the code is
executed..? | Wipro | 1 |
| int swap(int *a,int *b)
{
*a=*a+*b;*b=*a-*b;*a=*a-*b;
}
main()
{
int x=10,y=20;
swap(&x,&y);
printf("x= %d y = %d\n",x,y);
} | | 1 |
| #include<stdio.h>
main()
{
register i=5;
char j[]= "hello";
printf("%s %d",j,i);
} | | 1 |
| Extend the sutherland-hodgman clipping algorithm to clip
three-dimensional planes against a regular paralleiepiped | IBM | 1 |
| main()
{
printf("%d", out);
}
int out=100; | | 1 |
| void main()
{
char a[]="12345\0";
int i=strlen(a);
printf("here in 3 %d\n",++i);
} | | 1 |
| #include<stdio.h>
main()
{
int a[2][2][2] = { {10,2,3,4}, {5,6,7,8} };
int *p,*q;
p=&a[2][2][2];
*q=***a;
printf("%d----%d",*p,*q);
} | | 1 |
| |
| For more C Code Interview Questions Click Here |
Site Map
