| Other C Code Interview Questions |
| | | Question | Asked @ | Answers | | | | What is the subtle error in the following code segment?
void fun(int n, int arr[])
{
int *p=0;
int i=0;
while(i++<n)
p = &arr[i];
*p = 0;
} | | 1 | | #include<stdio.h>
main()
{
char s[]={'a','b','c','\n','c','\0'};
char *p,*str,*str1;
p=&s[3];
str=p;
str1=s;
printf("%d",++*p + ++*str1-32);
} | | 1 | | #define prod(a,b) a*b
main()
{
int x=3,y=4;
printf("%d",prod(x+2,y-1));
} | | 1 | | main( )
{
static int a[ ] = {0,1,2,3,4};
int *p[ ] = {a,a+1,a+2,a+3,a+4};
int **ptr = p;
ptr++;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
*ptr++;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
*++ptr;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
++*ptr;
printf(“\n %d %d %d”, ptr-p, *ptr-a, **ptr);
} | | 1 | | void main()
{
char a[]="12345\0";
int i=strlen(a);
printf("here in 3 %d\n",++i);
} | | 1 | | main()
{
int i;
clrscr();
for(i=0;i<5;i++)
{
printf("%d\n", 1L << i);
}
}
a. 5, 4, 3, 2, 1
b. 0, 1, 2, 3, 4
c. 0, 1, 2, 4, 8
d. 1, 2, 4, 8, 16 | HCL | 1 | | Finding a number which was log of base 2 | NetApp | 1 | | main()
{
signed int bit=512, i=5;
for(;i;i--)
{
printf("%d\n", bit >> (i - (i -1)));
}
}
a. 512, 256, 0, 0, 0
b. 256, 256, 0, 0, 0
c. 512, 512, 512, 512, 512
d. 256, 256, 256, 256, 256 | HCL | 1 | | How to return multiple values from a function?
| | 4 | | int i,j;
for(i=0;i<=10;i++)
{
j+=5;
assert(i<5);
} | | 1 | | main()
{
int i=300;
char *ptr = &i;
*++ptr=2;
printf("%d",i);
} | | 1 | | void main()
{
int i=i++,j=j++,k=k++;
printf(“%d%d%d”,i,j,k);
} | | 1 | | Give a very good method to count the number of ones in a 32
bit number.
(caution: looping through testing each bit is not a solution) | Microsoft | 5 | | main()
{
float i=1.5;
switch(i)
{
case 1: printf("1");
case 2: printf("2");
default : printf("0");
}
} | | 1 | | main()
{
int i=5;
printf(“%d”,i=++i ==6);
} | | 1 | | void main()
{
if(~0 == (unsigned int)-1)
printf(“You can answer this if you know how values are
represented in memory”);
} | | 1 | | main()
{
int i=-1,j=-1,k=0,l=2,m;
m=i++&&j++&&k++||l++;
printf("%d %d %d %d %d",i,j,k,l,m);
} | | 1 | | main()
{
int i, j, *p;
i = 25;
j = 100;
p = &i; // Address of i is assigned to pointer p
printf("%f", i/(*p) ); // i is divided by pointer p
}
a. Runtime error.
b. 1.00000
c. Compile error
d. 0.00000 | HCL | 1 | | How we will connect multiple client ? (without using
fork,thread) | TelDNA | 2 | | void main()
{
int i=10, j=2;
int *ip= &i, *jp = &j;
int k = *ip/*jp;
printf(“%d”,k);
} | | 1 | | | | For more C Code Interview Questions Click Here |
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