| Other C Code Interview Questions |
| |
| Question | Asked @ | Answers |
| |
| write a program in c to merge two array | | 1 |
| main()
{
int a[10];
printf("%d",*a+1-*a+3);
} | | 1 |
| main()
{
int i=10;
i=!i>14;
Printf ("i=%d",i);
} | | 1 |
| int i;
main(){
int t;
for ( t=4;scanf("%d",&i)-t;printf("%d\n",i))
printf("%d--",t--);
}
// If the inputs are 0,1,2,3 find the o/p | | 1 |
| main()
{
printf("\nab");
printf("\bsi");
printf("\rha");
} | | 1 |
| struct Foo
{
char *pName;
};
main()
{
struct Foo *obj = malloc(sizeof(struct Foo));
clrscr();
strcpy(obj->pName,"Your Name");
printf("%s", obj->pName);
}
a. Your Name
b. compile error
c. Name
d. Runtime error | HCL | 1 |
| What is the output for the following program
main()
{
int arr2D[3][3];
printf("%d\n", ((arr2D==* arr2D)&&(* arr2D ==
arr2D[0])) );
} | | 1 |
| main()
{
struct student
{
char name[30];
struct date dob;
}stud;
struct date
{
int day,month,year;
};
scanf("%s%d%d%d", stud.rollno, &student.dob.day,
&student.dob.month, &student.dob.year);
} | | 1 |
| How do you sort a Linked List (singly connected) in O(n)
please mail to pawan.10k@gmail.com if u can find an
anser...i m desperate to knw... | Oracle | 3 |
| main()
{
if (!(1&&0))
{
printf("OK I am done.");
}
else
{
printf("OK I am gone.");
}
}
a. OK I am done
b. OK I am gone
c. compile error
d. none of the above | HCL | 1 |
| void main()
{
int k=ret(sizeof(float));
printf("\n here value is %d",++k);
}
int ret(int ret)
{
ret += 2.5;
return(ret);
} | | 1 |
| Write a C function to search a number in the given list of
numbers. donot use printf and scanf | Honeywell | 4 |
| main()
{
int i=0;
for(;i++;printf("%d",i)) ;
printf("%d",i);
} | | 1 |
| #include<stdio.h>
main()
{
struct xx
{
int x;
struct yy
{
char s;
struct xx *p;
};
struct yy *q;
};
} | | 1 |
| write the function. if all the character in string B appear in
string A, return true, otherwise return false. | Google | 10 |
| Is the following statement a declaration/definition. Find
what does it mean?
int (*x)[10]; | | 1 |
| main()
{
int a=2,*f1,*f2;
f1=f2=&a;
*f2+=*f2+=a+=2.5;
printf("\n%d %d %d",a,*f1,*f2);
} | | 1 |
| #include <stdio.h>
main()
{
char * str = "hello";
char * ptr = str;
char least = 127;
while (*ptr++)
least = (*ptr<least ) ?*ptr :least;
printf("%d",least);
} | | 1 |
| String copy logic in one line. | NetApp | 9 |
| why java is platform independent? | Wipro | 10 |
| |
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