1) 1 -100 without looping....

#include<stdio.h>
#include<conio.h>
int i=1;
void main()
{
i<=100 ? printf("%d\n",i) : getch();  //conditional operator
i++;
main(); //recursive calling of main() function
}


7) printing a string without printf()

#include<stdio.h>
#include<conio.h>
void main()
{
if(printf("hello world"))
getch();
}

5) printing ur sequence

#include<stdio.h>
#include<conio.h>
void main()
{
int m;
printf("enter ur number:");
scanf("%d",&m);
for(int i=1;i<=m;i++)
{
for(int j=1;j<=m;j++)
printf("%d ",m);
printf("\n");
}
getch();
} 

6) printing 1-100 without using loops as well as control statement... 

same answer which i have made for your QUESTON 1... and conditional operator is not a control statement...

3) a) very basic and simple logic fabbonacci series:

#include<stdio.h>
#include<conio.h>
void main()
{
int a=1,b=-1,c,n;
printf("enter the no. of terms :");
scanf("%d",&n);
for(int i=1;i<=m;i++)
{
  c=a+b;
  printf("%d\n",c);
  b=a;
  a=c;
}
getch();
}

b) Factorial :

#include<stdio.h>
#include<conio.h>
void main()
{
int m,j=1;
printf("enter ur number :");
scanf("%d",&m);
for(int i=1;i<=m;i++)
j=j*i;
printf("the factorial is : j");
getch();
}

remaining i ll answer today evening....

thank u