Input is insufficient.size of the column is missing.
If size of the column is 300 x 300 mm, then the volume will
be
= 2x1.7x0.15 + (0.5-0.15)/3 x ((0.3x0.3+2.0x1.7+sqrt
((0.3x0.3)(2.0x1.7))
=0.981 m^3

suppose area at bottom A1 = (AxB) and area at top A2 (axb), where A,B,a,b are the respective lengths of footing top and bottom. further D is total depth and d is small depth of footing

formula is A1xd + (D-d)x(A1+A2 + sqroot {(A1xA2)/3}

Formula for trapezoidal footing quantity
Q = h/3{(a+b)+√ab}, a&b is area of bottom and top portion
=0.5/3{2x1.7+0.15x0.15+√3.4x0.0225}
=0.583 Cu.m.

Input is insufficient.size of the column is missing.
If size of the column is 300 x 300 mm, then the volume will be
=h/3(A1+A2+Sq root of A1square+A2square)
=((.5-.15)/3)(.09+3.4+(sq root of(.09 square + 3.4 square)))
=.116(3.49+(sq root of (11.5681))
=.116(3.49+3.401)
=.116*6.891
=.799 cum

Input is insufficient.size of the column is missing.
If size of the column is 300 x 300 mm, then the volume will be
=H/3(A1+A2+sq root of A1+A2)
=((0.5-0.15)/3)(3.4+0.09+ Sq root of 3.4+0.09)
=0.621 Cum

Here you have not given the column size.
So we assume column size 300mm X 300mm.
There is an Offset after the periphery of column & it is 75mm.
Rectangular Part
=L X B X H
=2 X 1.7 X 0.15
=0.51 cum
Trapezoidal Part
=(h/3)(A1 + A2 + SQRT ( A1 X A2 )
=((0.5-0.15)/3) ((2 X 1.7) + ((0.3+0.075)+(0.3+0.075)) + SQRT ((2 X 1.7) X ((0.3+0.075)+(0.3+0.075))
=0.12 ( 3.40 + 0.75 + 0.70 )
=0.57 cum
Total Concrete
=0.51 + 0.57
=1.08 cum

Difference between Ghol , Chimney & fly ash bricks b)Floor to floor height is 3m , rise=15cm , tread 20 cm , how to design staircase means steps landing