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Question
Trapezoidal footing length = 2m , B=1.7m D=0.5m and d-
0.15m. Can anybody help and calculate quantity of concrete 
by explaining all formulas involved.
 Question Submitted By :: Civil-Engineering
I also faced this Question!!     Answer Posted By  
 
Answer
# 1
Input is insufficient.size of the column is missing.
If size of the column is 300 x 300 mm, then the volume will
be
= 2x1.7x0.15 + (0.5-0.15)/3 x ((0.3x0.3+2.0x1.7+sqrt
((0.3x0.3)(2.0x1.7))
=0.981 m^3
 
Is This Answer Correct ?    76 Yes 29 No
Kishore Kumar
 
Answer
# 2
h(=D-d)\3 * A1+A2+SqrtA1A2 = Q1
A1*A2*thickness = Q2

Q = Q1 + Q2.
 
Is This Answer Correct ?    26 Yes 7 No
Vishal Gajjar
 
 
 
Answer
# 3
Q1=2.1*1.7*0.5
Q2=(0.5-0.15)/3*((A1+A2)+(SQRT A1*A2))
A1=Area of bottom portion
A2=Area of top portion
TOTAL QTY=Q1+Q2
 
Is This Answer Correct ?    17 Yes 3 No
Suresh,trichirapalli
 
Answer
# 4
Before calculating the quantity of concrete required for size of pillar or size of footing at (D=0.5 m)



Formula :- L X B X d + D-d/3 x A1 + A2 + √(A1 X A2)
 
Is This Answer Correct ?    18 Yes 6 No
S S Grewal
 
Answer
# 5
suppose area at bottom A1 = (AxB) and area at top A2 (axb), where A,B,a,b are the respective lengths of footing top and bottom. further D is total depth and d is small depth of footing

formula is A1xd + (D-d)x(A1+A2 + sqroot {(A1xA2)/3}
 
Is This Answer Correct ?    14 Yes 8 No
Manpreet Singh
 
Answer
# 6
Question is not complete because one must require top are to calculate volume for trapezoid. 
Is This Answer Correct ?    4 Yes 1 No
Ashish Parasiya
 
Answer
# 7
Formula for trapezoidal footing quantity
Q = h/3{(a+b)+√ab}, a&b is area of bottom and top portion
=0.5/3{2x1.7+0.15x0.15+√3.4x0.0225}
=0.583 Cu.m.
 
Is This Answer Correct ?    10 Yes 8 No
R. Ansari
 
Answer
# 8
Input is insufficient.size of the column is missing.
If size of the column is 300 x 300 mm, then the volume will be
=h/3(A1+A2+Sq root of A1square+A2square)
=((.5-.15)/3)(.09+3.4+(sq root of(.09 square + 3.4 square)))
=.116(3.49+(sq root of (11.5681))
=.116(3.49+3.401)
=.116*6.891
=.799 cum
 
Is This Answer Correct ?    4 Yes 2 No
R. Dilli Babu
 
Answer
# 9
Input is insufficient.size of the column is missing.
If size of the column is 300 x 300 mm, then the volume will be
=H/3(A1+A2+sq root of A1+A2)
=((0.5-0.15)/3)(3.4+0.09+ Sq root of 3.4+0.09)
=0.621 Cum
 
Is This Answer Correct ?    2 Yes 0 No
R. Suresh
 
Answer
# 10
Here you have not given the column size.
So we assume column size 300mm X 300mm.
There is an Offset after the periphery of column & it is 75mm.
Rectangular Part
=L X B X H
=2 X 1.7 X 0.15
=0.51 cum
Trapezoidal Part
=(h/3)(A1 + A2 + SQRT ( A1 X A2 )
=((0.5-0.15)/3) ((2 X 1.7) + ((0.3+0.075)+(0.3+0.075)) + SQRT ((2 X 1.7) X ((0.3+0.075)+(0.3+0.075))
=0.12 ( 3.40 + 0.75 + 0.70 )
=0.57 cum
Total Concrete
=0.51 + 0.57
=1.08 cum
 
Is This Answer Correct ?    1 Yes 0 No
Sagar Mistry
 

 
 
 
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