Re: Trapezoidal footing length = 2m , B=1.7m D=0.5m and d-
0.15m. Can anybody help and calculate quantity of concrete
by explaining all formulas involved.

Re: Trapezoidal footing length = 2m , B=1.7m D=0.5m and d-
0.15m. Can anybody help and calculate quantity of concrete
by explaining all formulas involved.

Input is insufficient.size of the column is missing.
If size of the column is 300 x 300 mm, then the volume will
be
= 2x1.7x0.15 + (0.5-0.15)/3 x ((0.3x0.3+2.0x1.7+sqrt
((0.3x0.3)(2.0x1.7))
=0.981 m^3

Re: Trapezoidal footing length = 2m , B=1.7m D=0.5m and d-
0.15m. Can anybody help and calculate quantity of concrete
by explaining all formulas involved.

Re: Trapezoidal footing length = 2m , B=1.7m D=0.5m and d-
0.15m. Can anybody help and calculate quantity of concrete
by explaining all formulas involved.

suppose area at bottom A1 = (AxB) and area at top A2 (axb), where A,B,a,b are the respective lengths of footing top and bottom. further D is total depth and d is small depth of footing

formula is A1xd + (D-d)x(A1+A2 + sqroot {(A1xA2)/3}

Re: Trapezoidal footing length = 2m , B=1.7m D=0.5m and d-
0.15m. Can anybody help and calculate quantity of concrete
by explaining all formulas involved.

Re: Trapezoidal footing length = 2m , B=1.7m D=0.5m and d-
0.15m. Can anybody help and calculate quantity of concrete
by explaining all formulas involved.

Re: Trapezoidal footing length = 2m , B=1.7m D=0.5m and d-
0.15m. Can anybody help and calculate quantity of concrete
by explaining all formulas involved.

Formula for trapezoidal footing quantity
Q = h/3{(a+b)+√ab}, a&b is area of bottom and top portion
=0.5/3{2x1.7+0.15x0.15+√3.4x0.0225}
=0.583 Cu.m.

Re: Trapezoidal footing length = 2m , B=1.7m D=0.5m and d-
0.15m. Can anybody help and calculate quantity of concrete
by explaining all formulas involved.

Re: Trapezoidal footing length = 2m , B=1.7m D=0.5m and d-
0.15m. Can anybody help and calculate quantity of concrete
by explaining all formulas involved.

Re: Trapezoidal footing length = 2m , B=1.7m D=0.5m and d-
0.15m. Can anybody help and calculate quantity of concrete
by explaining all formulas involved.

Input is insufficient.size of the column is missing.
If size of the column is 300 x 300 mm, then the volume will be
=h/3(A1+A2+Sq root of A1square+A2square)
=((.5-.15)/3)(.09+3.4+(sq root of(.09 square + 3.4 square)))
=.116(3.49+(sq root of (11.5681))
=.116(3.49+3.401)
=.116*6.891
=.799 cum

How to calculate the amount of Brick,cement & sand required
for 1 cum of 230mm thick brick work with ratio 1:5 please
give me an answer with detailed step