If the current of one side either primary or secondary is
known than the current of other side will be in same
proportion as the volotage ratio of primary and secondary
side.
For example -for a 1000 KVA 11kv/0.4 kv transformer if there
is 1 amp. current in HT side than current in LT side will be
1x11x1000/400 i.e almost 26 amps.

Let suppose u have taken 1500 kva transformer of 11kv to 415 v u wanna be the current calculation for the both HT side and LT side. But u also think that u have connect load of the transformer 1000 kw. In this case both HT & LT SIDE power drawn is same. But this is three phase so we take formula
P equal to SQ ROOT 3 *V* I COS phai
Remember cos phai is necessary becuse of we know KVA :::: KW/ COS phai
U have connect 1000kw and its drawn full lo
ad then it wil be calculate in HT SIDE
1000*1000:::1.732*11000*0.8* I(u take power factor as0.8)
I::::65.6A
WHILE calculating in LT SIDE IT wil be
1000*1000::: 1.732*440*0.8* I
I:::1739.05A
because power drawn HT & LT SIDE depend on load connected to the transformer

Hi friends.
m 3 years drop. now d company asks in d interview d reason
4 my drop.what shud b d probable answers 4 that which may
not put a negative impression.

is KVAR (not reverse power) relay necessary to protect from
excitor field failure on a brushless, synchroneus generator?
Some people with previos experince tell me no but the
manufacturers tell me it is designed for that purpose.
Is it that it is only necessary for brushless generators
and not the older style with the slip rings and brushes?

What will be the size of cable required for 5.5 KW motor (
Full load current 10 Amps approx.), Starting current with
DOL is 120 Amps. Aprrox. Short circuit current with LLLG
fault is 2000 Amps Approx.

what happens if number of poles in stator and rotor windins
of slip ring induction motor are not same. Will it rotate
near to the synchronus speed defined by stator?