#include <stdio.h>
int main ( int argc, char* argv [ ] )
{
int value1 = 10;
int value2 = 5;
printf ( "\n The sum is :%d", value1 | value2 );
}
This is the answer asked by some one to add two numbers
with out using arithmetic operator?Yes this answer is write
it given out put as 15.But how?????
what is need of following line?
int main ( int argc, char* argv [ ] )
how it work?what is the meaning for this line?
please explain me.Advance thanks
Re: #include <stdio.h>
int main ( int argc, char* argv [ ] )
{
int value1 = 10;
int value2 = 5;
printf ( "\n The sum is :%d", value1 | value2 );
}
This is the answer asked by some one to add two numbers
with out using arithmetic operator?Yes this answer is write
it given out put as 15.But how?????
what is need of following line?
int main ( int argc, char* argv [ ] )
how it work?what is the meaning for this line?
please explain me.Advance thanks
binary value of 10 = 1010
binary value of 5 = 0101
so if u do bitwise OR. u will get 1111, which is the binary
value of 15. Note: This will not work for all the case:
For eg, value1 = 5 and value2 = 5 will not give u 10.
Instead the printf will print 5 only.
Re: #include <stdio.h>
int main ( int argc, char* argv [ ] )
{
int value1 = 10;
int value2 = 5;
printf ( "\n The sum is :%d", value1 | value2 );
}
This is the answer asked by some one to add two numbers
with out using arithmetic operator?Yes this answer is write
it given out put as 15.But how?????
what is need of following line?
int main ( int argc, char* argv [ ] )
how it work?what is the meaning for this line?
please explain me.Advance thanks
hello deepak sir
ur answer is exactly write.Thank you sir.
But i want to know the meaning or this and how it work?
will u please explain me?
thanks.
what is need of following line?
int main ( int argc, char* argv [ ] )
Re: #include <stdio.h>
int main ( int argc, char* argv [ ] )
{
int value1 = 10;
int value2 = 5;
printf ( "\n The sum is :%d", value1 | value2 );
}
This is the answer asked by some one to add two numbers
with out using arithmetic operator?Yes this answer is write
it given out put as 15.But how?????
what is need of following line?
int main ( int argc, char* argv [ ] )
how it work?what is the meaning for this line?
please explain me.Advance thanks
In the printf statement, since the expression uses OR (|),
answer is correct.. 10 and 5 will be converted to its
binary equivalent.
10 = 1010
5 = 0101
10 | 5 1010
0101 gives 1111 which is 15....
Also main function takes only two arguments which
are "argc" and "argv".. thus the arguments are
mentioned...even if u just write main() without arguments,
no problem..
Re: #include <stdio.h>
int main ( int argc, char* argv [ ] )
{
int value1 = 10;
int value2 = 5;
printf ( "\n The sum is :%d", value1 | value2 );
}
This is the answer asked by some one to add two numbers
with out using arithmetic operator?Yes this answer is write
it given out put as 15.But how?????
what is need of following line?
int main ( int argc, char* argv [ ] )
how it work?what is the meaning for this line?
please explain me.Advance thanks
consider the following program sigment
int n,sum=1;
switch(n) {
case 2:sum=sum+2;
case 3:sum*=2;
break;
default:sum=0;}
if n=2, what is the value of sum
a.0
b.6
c.3
d.none
Given an array of numbers, except for one number all the
others occur twice. Give an algorithm to find that number
which occurs only once in the array.
Consider a language that does not have arrays but does have
stacks as a data type.and PUSH POP..are all defined .Show
how a one dimensional array can be implemented by using two
stacks.
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