The question requires more details.
First the "K" represents kilo or 1000.
The real power (kW) can be thought of as the x-axis and the
reactive power (kVar) from inductance or capacitance can be
thought of as the y-axis. The hypotenuse is the
Apparent power (KVA). The relationship of Real to apparent
power gives the Power Factor, where a power factor of 1.0
simply means that you only have real power, no reactive
power. The leading and lagging VARs from capacitance and
inductance, respectively can be added numerically since
they are on the same axis.
To ask, how muck kVars are required for a given kW doesn’t
make a lot of sense because you need to include the desired
If Pure Capacitor 90 Leads so The power factor is Unity(1)
*Sin(90)=1(But Reactive power is zero)
since I=Kvar/1.732*V*1 Eg. 1000/1.732*415*1=1.39A
other formula for Determine KW=KVAR/tan(pi)or KW=VIcos(PI)
Assume * cos(0.9)
since KW=KVAR/tan....Equ 1, take the cos invesr is equal to (0.9)=25.8419 ...Equ 2
they are more formulas
Hi,My name is ranms i want to know the machine vibration
related problems.post me if any body knows.
1) Possible causes of machine horizontal vibration high?
2) Possible causes of machine vertical vibration high?
3) Possible causes of machine axial vibration high?
In case of 11kV dual delta bank what are the recommended
protections with specific CT / VT requirements? The
capacitor bank is to be connected to the main 11kV
switchgear from where the H.V.Motors and auxiliary 440V