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Question
What the capacitor Current formula?, For 1 KVAr how amps 
its required? for using the KVAr for boosting the PF Design 
Calculation.( Eg: for 30 KVAr required how many KW?)
 Question Submitted By :: Electrical-Engineering
I also faced this Question!!     Answer Posted By  
 
Answer
# 1
As per my knowledge,
On my site bellow capacitor bank I am using.
I have 350 Kvar capacitor bank in this bank 25 kvar
capacitors are placed.

Capacitor specification

Volt = 440
Kvar = 25
Three Phase

KVA
I = ----------
Volt *1.732

25000
I = ----------
440 *1.732

I = 32.80 Amps


Eg 30 Kvar

KVA
I = ----------
Volt *1.732


30000
I = ----------
440 *1.732


I = 39.36 Amps
 
Is This Answer Correct ?    227 Yes 90 No
Shri..
 
Answer
# 2
You explained the answer in KVA? where do get the kva from
this variables, the formula for capacitor in KVAr, KVAr
into KW, KVA & Amps
 
Is This Answer Correct ?    65 Yes 17 No
Pasuvaraj
 
 
 
Answer
# 3
Kvar= 1.73*V*I*Sin$ ($ IS INSTESD OF PHASE ANGLE PHI)

so I= kVAR/1.73*V*SIN$

IN A PURELY CAPACITIVE CIRCUIT $ IS 90 DEGREE
SO TERM SIN 90 = 1
HENCE WE CAN CALCULATE CAPACITOR CURRENT BY kVAR/1.73*V
 
Is This Answer Correct ?    44 Yes 5 No
Prakesh
 
Answer
# 4
VOLT = 400
KVAr = 30
PHASE = 3

I = KVAr
-----
400 x 1.732
=43amps.
Kw = I x 0.624
= 26.8KW.
 
Is This Answer Correct ?    38 Yes 20 No
Jose
 
Answer
# 5
For correcting PF KVAr is introduced, thus formula

pf=cos A is significant

there you should have a desired PF. If for example you need
a power factor of .90 to maintain for a 30kVAR the watts
that would come will be:

A=arccos .90
A= 25.84

WATTs= KVAR/tan 25.84

= 62500 watts approx.

remember that for PF correnction it is the KVAR that is in
need of computation and not the watts so the question would
rather be, how much capacitor kVAR you need to correct the
power factor.
 
Is This Answer Correct ?    34 Yes 19 No
Arnie
 
Answer
# 6
Its 1.3A/KVAR 
Is This Answer Correct ?    25 Yes 10 No
Utkarsh
 
Answer
# 7
The question requires more details.
First the "K" represents kilo or 1000.
The real power (kW) can be thought of as the x-axis and the
reactive power (kVar) from inductance or capacitance can be
thought of as the y-axis. The hypotenuse is the
Apparent power (KVA). The relationship of Real to apparent
power gives the Power Factor, where a power factor of 1.0
simply means that you only have real power, no reactive
power. The leading and lagging VARs from capacitance and
inductance, respectively can be added numerically since
they are on the same axis.
To ask, how muck kVars are required for a given kW doesn’t
make a lot of sense because you need to include the desired
power factor.
 
Is This Answer Correct ?    18 Yes 6 No
Harry
 
Answer
# 8
** Capacitor Current formula is

I= kVAr/kV/1.732 ( for 3 ph capacitor )

**for 1 kVar capacitor... suppose voltage is 440 volts than,

I=1/0.440/1.732
I=1.31 Amps.

For all your information,generally 1 kVAr capacitor takes
0.5 watts...henceforth..

30 kvar capacitor required kw=30X0.5=15 watts and is 0.015kw

thanks!!!!!!!
 
Is This Answer Correct ?    7 Yes 5 No
9561354591
 
Answer
# 9
dear,sir

my answer is 1 kvar = 1.3122 will be

my 2nd answer is 30 kvar= 44.5 kw will be and the mantioned
by powr factor like this,current cos(f1)and (requred cos(f2)

if my answer is correct then i shall be obligged to you
 
Is This Answer Correct ?    1 Yes 0 No
Mohammad Rafique
 
Answer
# 10
Q = VIsin(fi)

capacitor current = I = Q/Vsin(fi)

For , 230 v and power factor angle 90 ,then

I = 1/230*sin 90 = 4.32 amp.

If power factor angle is 36.89 (power factor 0.8)
,then

P/Q = kw/KVAR = VIcos(fi)/VIsin(fi)

P/Q = cos(fi)/sin(fi) = Tan(fi)

P = Q tan(fi)

P = 30 tan(36.89) = 30 * 0.75 = 22.5 Kw
 
Is This Answer Correct ?    1 Yes 0 No
Sagar
 

 
 
 
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