table:employee
EID ENAME MID(manager ids)
101 rama null
102 sita 101
103 siva 101
104 ganesh 103
. . .
. . .
for 103 ID the manager ID is 101(RAMA) and for 104 manager
is SIVA
if i give employee id (EID) you have to tell the manager for
that EID write query?
eample:if i give 102 .The query output should be manager for
102 ID that it should print RAMA as output
Question Submitted By :: Om Namo Bhagavathe Vasudevaya
Re: table:employee
EID ENAME MID(manager ids)
101 rama null
102 sita 101
103 siva 101
104 ganesh 103
. . .
. . .
for 103 ID the manager ID is 101(RAMA) and for 104 manager
is SIVA
if i give employee id (EID) you have to tell the manager for
that EID write query?
eample:if i give 102 .The query output should be manager for
102 ID that it should print RAMA as output
create table emp (eid int, ename varchar(50),mid int)
insert into emp values(1,'Ganesh',null)
insert into emp values(2,'Ramesh',1)
insert into emp values(3,'Suresh',1)
insert into emp values(4,'Selvam',2)
insert into emp values(5,'Vignesh',3)
select * from emp
Declare @eid int
Set @eid = 4 -- Your Input ID here..
Select 'Manager For '+CONVERT(VARCHAR,emp2.eid)+' --> '+ emp1.ename
From emp emp1
Inner join emp emp2 on emp1.eid = emp2.mid and emp2.eid = @eid
Re: table:employee
EID ENAME MID(manager ids)
101 rama null
102 sita 101
103 siva 101
104 ganesh 103
. . .
. . .
for 103 ID the manager ID is 101(RAMA) and for 104 manager
is SIVA
if i give employee id (EID) you have to tell the manager for
that EID write query?
eample:if i give 102 .The query output should be manager for
102 ID that it should print RAMA as output
select ename from employee
where eid = (select case mid when null then aid
else mid end mid
where eid=@aid
)
select m.name from employee e
join employee m on (m.aid=e.mid)
Re: table:employee
EID ENAME MID(manager ids)
101 rama null
102 sita 101
103 siva 101
104 ganesh 103
. . .
. . .
for 103 ID the manager ID is 101(RAMA) and for 104 manager
is SIVA
if i give employee id (EID) you have to tell the manager for
that EID write query?
eample:if i give 102 .The query output should be manager for
102 ID that it should print RAMA as output
create table #emp (eid int, ename varchar(50),mid int)
insert into #emp values(1,'Ganesh',null)
insert into #emp values(2,'Ramesh',1)
insert into #emp values(3,'Suresh',1)
insert into #emp values(4,'Selvam',2)
insert into #emp values(5,'Vignesh',3)
declare @aid int
set @aid =1
select ename from #emp
where eid = (select case isnull(mid,0) when 0 then eid
else mid end mid
from #emp
where eid=@aid
)
select m.ename from #emp e
join #emp m on (m.eid=isnull(e.mid,e.eid))
where e.eid=1
Re: table:employee
EID ENAME MID(manager ids)
101 rama null
102 sita 101
103 siva 101
104 ganesh 103
. . .
. . .
for 103 ID the manager ID is 101(RAMA) and for 104 manager
is SIVA
if i give employee id (EID) you have to tell the manager for
that EID write query?
eample:if i give 102 .The query output should be manager for
102 ID that it should print RAMA as output
Declare @eid int
Set @eid=2
select 'The manager for employee id '+convert(varchar
(50),e2.eid)+' is '+e1.ename from emp e1,emp e2
where e1.eid=e2.mid and e2.eid=@eid
Re: table:employee
EID ENAME MID(manager ids)
101 rama null
102 sita 101
103 siva 101
104 ganesh 103
. . .
. . .
for 103 ID the manager ID is 101(RAMA) and for 104 manager
is SIVA
if i give employee id (EID) you have to tell the manager for
that EID write query?
eample:if i give 102 .The query output should be manager for
102 ID that it should print RAMA as output
-- create table #Employees (EID int, EName varchar(20), MID
int)
-- insert #Employees values(101,'Rama',NULL)
-- insert #Employees values(102,'Sita',101)
-- insert #Employees values(103,'Shiva',101)
-- insert #Employees values(104,'Ganesh',103)
--for 103 ID the manager ID is 101(RAMA) and for 104
manager is SIVA
--Write a script which displays Shiva's Manager's name.
select a.EID, a.EName, a.MID, b.EName
from #Employees a
inner join #Employees b on a.mid=b.eid and a.EName='Shiva'
please can anyone answer this query
Table 1 has 2 columns: EmployeeId,Age
Table 2 has 2 columns: EmployeeId, Region
Write SQL to Find the region who has the oldest person
There is table like Events...in that name ,startdate
,enddate,location are the column names
write a stored Procedure for this table to get events by
Months "GetEventsByMonths"
hi, may i know what is the command to get abstract the
current month, current year and current day from a given
date.i want these three in a isolated way..seperatedly is
that any way in sql server 2000