what is the output of the following program?
main()
{
int c[]={2,8,3,4,4,6,7,5};
int j,*p=c,*q=c;
for(j=0;j<5;j++)
{
printf("%d",*c);
++q;
}
for(j=0;j<5;j++)
{
printf("%d",*p);
++p;
}
}
Re: what is the output of the following program?
main()
{
int c[]={2,8,3,4,4,6,7,5};
int j,*p=c,*q=c;
for(j=0;j<5;j++)
{
printf("%d",*c);
++q;
}
for(j=0;j<5;j++)
{
printf("%d",*p);
++p;
}
}
Re: what is the output of the following program?
main()
{
int c[]={2,8,3,4,4,6,7,5};
int j,*p=c,*q=c;
for(j=0;j<5;j++)
{
printf("%d",*c);
++q;
}
for(j=0;j<5;j++)
{
printf("%d",*p);
++p;
}
}
2222228344...
the above code can be remodified as :
printf("%d",*q); in first printf statement to get the same
output for both printf statements
thank u
Re: what is the output of the following program?
main()
{
int c[]={2,8,3,4,4,6,7,5};
int j,*p=c,*q=c;
for(j=0;j<5;j++)
{
printf("%d",*c);
++q;
}
for(j=0;j<5;j++)
{
printf("%d",*p);
++p;
}
}
output is 2222228344
in loop 1
as we know that array variable contain the base address of
the array
*c means we are trying to print the value of contained in
the base address which is not changed in the loop
note we can't change the base address of the array that is
we can't do 'c++'
as in loop for 5 times contain of the base address will be
printed as
22222
in loop 2
in assigned base address of the array to pointer p
here we are printing the contain of address stored in p and
increment the value of p ( that is pointing to the next
element of the array )
so we will get output for 2nd loop is
28344
overall answer is
2222228344
if any wroung in my aswer plz info me at
molugu.ashwin@gamil.com
Re: what is the output of the following program?
main()
{
int c[]={2,8,3,4,4,6,7,5};
int j,*p=c,*q=c;
for(j=0;j<5;j++)
{
printf("%d",*c);
++q;
}
for(j=0;j<5;j++)
{
printf("%d",*p);
++p;
}
}
#include <stdio.h>
int main ( int argc, char* argv [ ] )
{
int value1 = 10;
int value2 = 5;
printf ( "\n The sum is :%d", value1 | value2 );
}
This is the answer asked by some one to add two numbers
with out using arithmetic operator?Yes this answer is write
it given out put as 15.But how?????
what is need of following line?
int main ( int argc, char* argv [ ] )
how it work?what is the meaning for this line?
please explain me.Advance thanks
#include<stdio.h>
int fun();
int i;
int main()
{
while(i)
{
fun();
main();
}
printf("hello \n");
return 0;
}
int fun()
{
printf("hi");
}
answer is hello.how??wat is tat while(i) mean?
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