How to calculate unit consumption on the basis of load.
kWH=kwXhrs.is it correct? kw is motor load.What is unit
consumption at 100% load, 50% load & on no load.

But while you need to calculate the KWH consumed by a motor,
multiplying KW of motor (nameplate KW) and hour will not
give you the energy consumed. This is because the name plate
KW in a motor is not the electrical power, but the
mechanical power output provided by the motor (Electrical
Power = Frictional losses + Eddy current losses + Copper
losses + air gap losses + Mechanical power). In order to
calculate the energy consumed by the motor you can use the
formula

single phase AC = Voltage x Rated current x Power factor x
Hrs run. (100% load)

3 Phase AC = 1.732 x Voltage x Rated Current x Power factor
x Hrs run. (100% load)

Normally the power factor of motor is considered between 0.8
to 0.85 at full load operation.

At no-load, motor will take approx 40% of its rated full
load current (again this depends on the design of motor, but
normally assumed to be near 40%). So at 50% load, the motor
will take a current around 70 to 75% of its full load rated
current. so we can approximate as

energy consumed at 50% load (motor - 3 phaase) = 1.732 x
Voltage x 75% rated full load current x power factor x Hrs run .

at no load = 1.732 x Voltage x 40% of rated current x power
factor x Hrs run.

we want install 11KV generator to supply power 12km far
from the power house.Load to be fed is 1MW.which conductor
should we use and wat will be transmission line losses?