| Other C Interview Questions |
| |
| Question | Asked @ | Answers |
| |
| 18)struct base {int a,b;
base();
int virtual function1();
}
struct derv1:base{
int b,c,d;
derv1()
int virtual function1();
}
struct derv2 : base
{int a,e;
}
base::base()
{
a=2;b=3;
}
derv1::derv1(){
b=5;
c=10;d=11;}
base::function1()
{return(100);
}
derv1::function1()
{
return(200);
}
main()
base ba;
derv1 d1,d2;
printf("%d %d",d1.a,d1.b)
o/p is
a)a=2;b=3;
b)a=3; b=2;
c)a=5; b=10;
d)none
19) for the above program answer the following q's
main()
base da;
derv1 d1;
derv2 d2;
printf("%d %d %d",da.function1(),d1.function1(),d2.function1
());
o/p is
a)100,200,200;
b)200,100,200;
c)200,200,100;
d)none
20)struct {
int x;
int y;
}abc;
you can not access x by the following
1)abc-->x;
2)abc[0]-->x;
abc.x;
(abc)-->x;
a)1,2,3
b)2&3
c)1&2
d)1,3,4
| | 1 |
| Which of the following are valid "include" formats?
A)#include and #include[file.h]
B)#include (file.h) and #include
C)#include [file.h] and #include "file.h"
D)#include <file.h> and #include "file.h"
| Accenture | 14 |
| Determine the code below, tell me exactly how many times is
the operation sum++ performed ?
for ( i = 0; i < 100; i++ )
for ( j = 100; j > 100 - i; j--)
sum++; | ITCO | 3 |
| Tell us the difference between these two :
#include"stdio.h"
#include<stdio.h>
define in detial. | | 4 |
| #define MAX(x,y) (x) > (y) ? (x) : (y)
main()
{
int i = 10, j = 5, k = 0;
k = MAX(i++, ++j);
printf("%d %d %d", i,j,k);
}
what will the values of i , j and k?
}
| NDS | 9 |
| 6)swap(int x,y)
{
int temp;
temp=x;
x=y;
y=temp;
}
main()
{
int x=2;y=3;
swap(x,y);
}
after calling swap ,what are yhe values x&y?
| | 2 |
| Who is invented by c? | Infosys | 14 |
| Is the following code legal?
struct a
{
int x;
struct a b;
}
| | 3 |
| what is the difference between arrays and linked list | Tech-Mahindra | 15 |
| in C-programming language without using printf statement
can we get output r not ? if yes how and if no also how ?
| | 6 |
| Write a routine that prints out a 2-D array in spiral order! | Lucent | 1 |
| i want explaination about the program and its stack reprasetaion
fibbo(int n)
{
if(n==1 or n==0)
return n;
else
return fibbo(n-1)+fibbo(n-2);
}
main()
{
fibbo(6);
}
| | 2 |
| 2)#include<iostream.h>
main()
{
printf("Hello World");
}
the program prints Hello World without changing main() the
o/p should
be
intialisation
Hello World
Desruct
the changes should be
a)iostream operator<<(iostream os, char*s)
os<<'intialisation'<<(Hello World)<<Destruct
b) c) d)none of the above | Siemens | 4 |
| main()
{
int i=400,j=300;
printf("%d..%d");
}
| ME | 8 |
| void main()
{int a[5],i,b=16;
for(i=0;i<5;i++)
a[i]=2*i;
f(a,5,b);
for(i=0;i<5;i++)
printf("\n %d",a[i]);
printf("\n %d",b);
}
f(int *x,int n,int y)
{
int i;
for(i=0;i<n;i++)
*(x+i)+=2;
y=y+2;
}wat r the errors in the prg.and improvise the prg to get o/p.? | | 2 |
| a memory of 20 bytes is allocated to a string declared as
char *s then the following two statements are executed:
s="Etrance"
l=strlen(s);
what is the value of l ?
a.20
b.8
c.9
d.21
| TCS | 4 |
| what is the difference between #include<> and #include”…”? | | 1 |
| pgm in c to reverse string by word using array(god is love
becomes love is god)
(no additional array can used,space is only delimiter
between words ) | Persistent | 1 |
| size maximum allocated by calloc() | DELL | 1 |
| n=7623
{
temp=n/10;
result=temp*10+ result;
n=n/10
}
| Wipro | 4 |
| |
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