write the function int countchtr(char string[],int ch);which returns the

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Question

write the function int countchtr(char string[],int 
ch);which returns the number of timesthe character ch 
appears in the string. for example the call countchtr("she 
lives in Newyork",'e') would return 3.

Question Submitted By :: Umayal

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Answer Posted By

Re: write the function int countchtr(char string[],int ch);which returns the number of timesthe character ch appears in the string. for example the call countchtr("she lives in Newyork",'e') would return 3.

Answer
# 1

#include<stdio.h>
#include<conio.h>
int string(char *,char);
void main()
{
char str[100],ch;
int c;
printf("enter the string :");
gets(str);
printf("enter the character to be searched :");
scanf("5c",&ch);
c=string(&str[0],ch);
printf("the character %c occurs for %d times ",ch,c);
getch();
}
int string(char *a,char ch)
{
int count=0;
  for(int j=0;*a!='\0';j++)
{
   if(*a==ch)
{
count++;
*(a++);
}
}
return count;
}

Is This Answer Correct ?

4 Yes

2 No

Vignesh1988i

Answer
# 2

int countchtr(char *str, char ch)
{
   int count=0;
   char *itr = str;
   while (*itr != '\0')
   {
       if(*itr == ch)
       {
          count++
       }
       itr++;
   }
   return count;
}

Is This Answer Correct ?

4 Yes

0 No

Goloap

Answer
# 3

a small change..............

#include<stdio.h>
#include<conio.h>
int string(char *,char);
void main()
{
char str[100],ch;
int c;
printf("enter the string :");
gets(str);
printf("enter the character to be searched :");
scanf("5c",&ch);
c=string(&str[0],ch);
printf("the character %c occurs for %d times ",ch,c);
getch();
}
int string(char *a,char ch)
{
int count=0;
  for(int j=0;*a!='\0';j++)
{
   if(*a==ch)
{
count++;
*a++;
}
}
return count;
}

Is This Answer Correct ?

3 Yes

0 No

Vignesh1988i

Answer
# 4

#include<stdio.h>
#include<conio.h>
int string(char *,char);
void main()
{
char str[100],ch;
int c;
printf("enter the string :");
gets(str);
printf("enter the character to be searched :");
scanf("5c",&ch);
c=string(&str[0],ch);
printf("the character %c occurs for %d times ",ch,c);
getch();
}
int string(char *a,char ch)
{
int count=0;
  for(int j=0;*a!='\0';j++)
{
   if(*a==ch)
{
count++;
*(a++);
}
}
return count;
}

Is This Answer Correct ?

0 Yes

0 No

Jagjit

Question	Asked @	Answers
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