// 
// MAIN -- Program to Purge a given character from a string.
// I/P example: ./a.out Bangalore a
// -- Sandeep Ambekar 

#include <stdio.h>
#define TRUE  1
#define FALSE 0

void
purge_char_from_string (char *str, char *c)
{
  int i, k, flag, count;        // i/j for index, flag to
keep track of
  // 'c' and count for iteration..
  char *buf = str;              // save the original string
start:
  str = buf;                    // we could enter the loop
again.
  i = 0;
  k = 1;
  count = 0;
  flag = FALSE;                 // INIT variables...
  printf ("Input String [%s] [%c] \n", str, *c);

  while (str[i] != '\0')
    {
      printf ("\t (%c) <==> (%c)\n", str[i], str[k]);
      if (str[i] == c[0])
        {
          str[i] = str[k];
          flag = TRUE;
          count++;
        }
      else if (flag == TRUE)
        {
          str[i] = str[k];      // later have a while loop
to find a char
          // to which is !c and replace them.
        }
      i++;
      k++;
    }
  printf ("[%s]\n", buf);
  if ((count - 1) >= 1)
    goto start;
}                               // end of
purge_char_from_string ....

// 
// MAIN -- Program to Purge a given character from a string.
// 

int
main (int argc, char *argv[])
{
  if (argc < 3)
    {
      printf ("Input <String> <char> \n");
      return 1;
    }
  printf (" ## Input  string %s : Char [%s]\n", argv[1],
argv[2]);
  purge_char_from_string (argv[1], argv[2]);

  printf (" Trimmed String ---> %s\n", argv[1]);
  return 0;
}                               // end of main..

#include<iostream>
using namespace std;
#include<string.h>
int main()
{
char string[]="lhellolollla";
int i=0;
int count=0;
while(i<strlen(string))
{
	while(string[i+count]=='l')
		count++;
	string[i]=string[i+count];
	i++;
	
}
printf("%s",string);
}

best of luck for tomorrow's test

in above solution  while loop iterates for only 6 times