Impedance voltage of a transformer is the voltage required
to

short circuit the secondary winding terminals of the
transformer and apply voltage gradually from zero at
primary winding.increase the voltage gradullay till the
full load current flows in the secondary.The voltage at
which full load current flows that voltage is the impedance
voltage of the transformer.This is required for short
circuit calculations.You can find on the transformer name
plate as Impedance voltage or percentage impedance.

impedence voltage is that voltage which is applied through
primary side and full load current is flowing in secondary
side whwnever short Ckt. of secondary side

This is the voltage required to drive full load current in a
winding of a transformer when the other winding is short
circuited.
for example if percentage impedance of a 33/11kv transformer
is 6%. it means that 33x6/100=1.98KV would be required to
drive full load current in 33kv winding when 11kv winding is
short circuited.

Impedance voltage of a transformer is the voltage required

to

short circuit the secondary winding terminals of the
transformer and apply voltage gradually from zero at
primary winding.increase the voltage gradullay till the

full load current flows in the secondary.The voltage at

which full load current flows that voltage is the impedance

voltage of the transformer.This is required for short
circuit calculations.You can find on the transformer name

plate as Impedance voltage or percentage impedance

Simply it is the percentage of the normal terminal voltage
required to circulate full-load current under short circuit
conditions, or can also be consider as the voltage drop of
the trafo..

The percentage impedance of a transformer is the volt drop
on full load due to the winding resistance and leakage
reactance expressed as a percentage of the rated voltage."

"It is also the percentage of the normal terminal voltage at
on side required to circulate full-load current under short
circuit conditions on other side."

The impedance of a transformer has a major effect on system
fault levels. It determines the maximum value of current
that will flow under fault conditions.

It is easy to calculate the maximum current that a
transformer can deliver under symmetrical fault conditions.
By way of example, consider a 2 MVA transformer with an
impedance of 5%. The maximum fault level available on the
secondary side is:

2 MVA x 100/5 = 40 MVA

and from this figure the equivalent primary and secondary
fault currents can be calculated.

A transformer with a lower impedance will lead to a higher
fault level (and vice versa).

The figure calculated above is a maximum. In practice, the
actual fault level will be reduced by the source impedance,
the impedance of cables and overhead lines between the
transformer and the fault, and the fault impedance itself.

it is % of rated primary voltage which require to establish
sufficient flux to produce full load current in short
circuited secondary, it is used while load loss test on
transformer.

Impedance voltage is calculated with short-circuit
test.which is very low compared to rated voltage. Impedance
voltage is the voltage which circulates the rated currents
when one of the two windings is shorted.

why do we require
two lines one
phase and a
neutral for an ac
transmission..is
neutral potential
zero..?if yes y
carry a neutral
line from
generating
station
itself...why dont
we take it from
ground

we hav seen in electric engine of trains only 1 wired slidng
conecctn is there frm ovrhead line,howevr to complete a ckt
in dc postv n negtv two conection has to b there...so where
is tht negative is been connectd or where it is grounded...?

what is the problem in manufacturing transformer with 0
degree phase displacement.???why alwasys go for DYn11 or
DY5?Whys not DY0 i.e zero degree displacement between
primary and secondary side vectors?