ya we can return two or more than two values..... it's
possible..
by using concept of POINTERS..... but no need of return
keyword at all.....
instead of call by value in the function use call by
reference concept....
take the following program:
int fun(int *,int *);
void main()
{
int j=800,k=1000;
fun(&j,&k);
printf("%d",j,k);
getch();
}
int fun(int *q,int *w)
{
q=q/2;
w=w/2;
}
the output of the followiung is : 400 & 500.
how it's possible, i ll explain,
since we are calling by reference we
are sending the address of the two variables. so in fun.
definition we are catching it by pointers..... so that
pointer variable is holding the address of the two variables
in main fun. which is passed through address.... so in the
function we are changing the values of j & k.... so this
will change the value directly in the address of those two
variables j & k....... so implicitely two values are
returned wit out return keyword....
yes we can return two or more values from a function using
return keyword...
Use structure...return type of the function will b 'struct'
and v ll store value in struct type.
Using the return statement u can only return one value at a
time.
So you can either return the value of a variable like you
can return an integer, or you can return pointer (which may
contain more than one values), which is pointing to
dynamically allocated location, Like in given below example:
//Returning two values from a function.
#include "stdio.h"
#include "malloc.h"
int *values()
{
int *ptr;
ptr = (int*)malloc(2);
*ptr = 10;
*(ptr+1) = 20;
return ptr;
}
int main()
{
int *ptr = values();
printf("%d\n%d",*ptr,*(ptr+1));
return 0;
}