#include<stdio.h>
main()
{
if(printf("hello")==0)
        printf("hello");
else
        printf("world");
}

Think is there any Other.....

#include<stdio.h>
void main()
{
	if(1)
	{
		printf("HELLO!");
		goto HERE;
	}
	else
	{
		HERE:
			printf("HAI....");
	}
}

but goto is not a good sort of programming ............. a 
well knowledgeable programmer wont use goto..... according 
to me........... plz think of any other logic??????????

but yhe printf statement will print one "hello" and one 
world.......................... but i said it must enter to 
the if part as well as else part controls.............. 
before a long time baxk itself i tried this method......... 
then only i read the question of IBM properly

//#include<stdio.h>
main()
{
 if(1)
  printf("hello");
  else;
  printf("world");
}

#include <stdio.h>

int main ( int argc, char* argv[] )
{
	if ( !printf("Hello") )
		printf ("Hello");
	else printf (" World");
}

int a=5,b=5;
 if(a==5)
 printf("hello");
 else;
 printf("world");

#include<stdio.h>
#include<conio.h>
main()
{
static int i;
if(i==0)
{
printf("HELLO");
i=i+1;
main();
}
else
prinf("WORLD");
getch();
}

/* Solution 1: */

int main(int argc, char* argv[])
{	
	if( argc == 2 || main( 2, NULL ) )
	{
		printf("Hello ");	
	}
	else
	{
		printf("World\n");
	}
	return 0;
}

/* Solution 2 (Only for Unix and Linux): */

int main(int argc, char* argv[])
{	
	if( !fork() )
	{
		printf("Hello ");	
	}
	else
	{
		printf("World\n");
	}
	return 0;
}