#
#
void main()
{
int num,n1,n2,sum;
cout<<"enter a 4 digit no.";
cin>>num;
n1=num/1000;
n2=num%10;
sum=n1+n2;
cout<<"sum of 1st & 4th digit is"<<sum;
}

#include<stdio.h>
main()
{
int n,n1,n4;
printf("Enter 4 digit number:");
scanf("%d",&n);
n4=n%10;
n1=n/100;
printf("\nResult=",(n1+n4));
getch();
}

thiz z how 2 find the sum of first and last digit of any 
number

#include<stdio.h>
#include<conio.h>
#include<math.h>
main()
{
long int n,nf,nl,temp;
int count=-1;
printf("Enter a number:");
scanf("%ld",&n);
temp =n;
while(temp<0)
{
  temp=temp/10;
c++;
}
nl=n%10;
nf=n/(pow(10,c));
printf("\n%ldResult=",(nf+nl));
getch();
}

#include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
int num,n1,n2,sum;
clrscr();
printf("Enter 4 digit number:");
scanf("%d",&num);
n1=num/1000;
n2=num%10;
sum=n1+n2;
printf("Sum of 1st & 4th digit number is=%d",sum);
getch();
}
enjoy!!!!!!!!!!!!

any program just mail me:
ssmartinp@gmail.com