Hello. For our university experiment (power transmission 
lines) , at first,
we only had a resistive load, and it was shown that
the sending end voltage is bigger than receiving end 
voltage. However, when the capacitive load was added in 
parallel to the resistive load, it was shown that the 
sending end voltage was approximately equal to the 
receiving end voltage. Why is it so?

Thank you and have a great day.

When resistive load connected then will be voltage drop ( 
Vd=I^2R Losses are Directly per potion to square of 
current ), there for sending end voltage higher then 
receiving end voltage 
If connected capacitive load then bothe voltage my be equal 
or receiving end voltage higher due lie capacitance, like 
the theory of capacitor

Dear Frnds

as we all knows that the total power is equal to real power 
plus reactive power. we have resistive as well as 
capacitive loads in general.

since we cant make any changes to reduce the resistive load 
we are adding a capacitor banks to match the voltage. 
capacitors have the caracteristic that it can store a 
voltage. when we add a capacitor obviously the stored 
energy in the capacitor will be added to the total voltage.

Regards,

Gatzrulz

generally we r used resistive load but whenever capacitive 
load is to be paralled with it which will improved power 
factor and minimize voltage drop due to resistance so 
losses will be less and we will get same sending end power 
or more at receiving end

i think this is right answer but if my ans. is wrong then 
inform me