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| Question |
fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}
above function is called as:
fun(10);
what will it print?
} | |
Question Submitted By :: Sid08 | |
I also faced this Question!! |
Rank |
Answer Posted By | | |
|
Re: fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}
above function is called as:
fun(10);
what will it print?
} |
Answer
# 1 | 0 1 2 5 10  |
| Guest
| | |
|
Re: fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}
above function is called as:
fun(10);
what will it print?
} |
Answer
# 2 | 5 |
| Megha
| | | |
| | | | |
|
Re: fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}
above function is called as:
fun(10);
what will it print?
} |
Answer
# 3 | 0 |
| Divya
| | |
|
Re: fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}
above function is called as:
fun(10);
what will it print?
} |
Answer
# 4 | 0 1 2 5 10...Please don't post the wrong answer. |
| Raj
| | |
|
Re: fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}
above function is called as:
fun(10);
what will it print?
} |
Answer
# 5 | it will print "0" i.e zero since compiler wont get to the
print statement until the value is zero. |
| Mortal
| | |
|
Re: fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}
above function is called as:
fun(10);
what will it print?
} |
Answer
# 6 | Guest & Raj is correct.......
Please don't post the wrong answer if u r not clear about this |
| Code
| | |
|
Re: fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}
above function is called as:
fun(10);
what will it print?
} |
Answer
# 7 | 0 1 2 5 10 is the answer. But can anybody explain why the
printing order 0 1 2 5 10. Why not 10 5 2 1 0 ? please...
Is it depends on stack allocation?? |
| Gg
| | |
|
Re: fun(int x)
{
if(x > 0)
fun(x/2);
printf("%d", x);
}
above function is called as:
fun(10);
what will it print?
} |
Answer
# 8 | 10,5,2,1
after that it terminated. |
| Vinay
| | | | |
| | |
|
|
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